Given a point (X, Y) in a 2-D plane and an integer K, the task is to check whether it is possible to move from (0, 0) to the given point (X, Y) in exactly K moves. In a single move, the positions that are reachable from (X, Y) are (X, Y + 1), (X, Y – 1), (X + 1, Y) and (X – 1, Y).
Input: X = 0, Y = 0, K = 2
Move 1: (0, 0) -> (0, 1)
Move 2: (0, 1) -> (0, 0)
Input: X = 5, Y = 8, K = 20
Approach: It is clear that the shortest path to reach (X, Y) from (0, 0) will be minMoves = (|X| + |Y|). So, if K < minMoves then it is impossible to reach (X, Y) but if K ≥ minMoves then after reaching (X, Y) in minMoves number of moves the remaining (K – minMoves) number of moves have to be even in order to remain at that point for the rest of the moves.
So it is possible to reach (X, Y) from (0, 0) only if K ≥ (|X| + |Y|) and (K – (|X| + |Y|)) % 2 = 0.
Below is the implementation of the above approach:
- Check if it is possible to move from (0, 0) to (x, y) in N steps
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- Print steps to make a number in form of 2^X - 1
- Minimum steps required to reach the end of a matrix | Set 2
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