# Check if a Queen can attack a given cell on chessboard

Given the position of the queen (qX, qY) and the opponent (oX, oY) on a chessboard. The task is to determine whether the queen can attack the opponent or not. Note that the queen can attack in the same row, same column and diagonally.

Example:

Input: qX = 4, qY = 5, oX = 6, oY = 7
Output: Yes
The queen can attack diagonally.

Input: qX = 1, qY = 1, oX = 3, oY = 2
Output: No

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

• If qR = oR, it means that both the queen and the opponent are in the same row and the queen can attack the opponent.
• Similarly, if qC = oC then also the queen can attack the opponent as they both are in the same column.
• And for diagonals, if abs(qR – oR) = abs(qC – oC) i.e. queen can attack the opponent diagonally.

If all of the above conditions fail then the opponent is safe from the queen.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function that returns true if the queen ` `// can attack the opponent ` `bool` `canQueenAttack(``int` `qR, ``int` `qC, ``int` `oR, ``int` `oC) ` `{ ` `    ``// If queen and the opponent are in the same row ` `    ``if` `(qR == oR) ` `        ``return` `true``; ` ` `  `    ``// If queen and the opponent are in the same column ` `    ``if` `(qC == oC) ` `        ``return` `true``; ` ` `  `    ``// If queen can attack diagonally ` `    ``if` `(``abs``(qR - oR) == ``abs``(qC - oC)) ` `        ``return` `true``; ` ` `  `    ``// Opponent is safe ` `    ``return` `false``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `qR = 1, qC = 1; ` `    ``int` `oR = 3, oC = 2; ` `    ``if` `(canQueenAttack(qR, qC, oR, oC)) ` `        ``cout << ``"Yes"``; ` `    ``else` `        ``cout << ``"No"``; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `class` `GFG ` `{ ` `     `  `// Function that returns true if the queen ` `// can attack the opponent ` `static` `boolean` `canQueenAttack(``int` `qR, ``int` `qC, ` `                                ``int` `oR, ``int` `oC) ` `{ ` `    ``// If queen and the opponent ` `    ``// are in the same row ` `    ``if` `(qR == oR) ` `        ``return` `true``; ` ` `  `    ``// If queen and the opponent  ` `    ``// are in the same column ` `    ``if` `(qC == oC) ` `        ``return` `true``; ` ` `  `    ``// If queen can attack diagonally ` `    ``if` `(Math.abs(qR - oR) == Math.abs(qC - oC)) ` `        ``return` `true``; ` ` `  `    ``// Opponent is safe ` `    ``return` `false``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `qR = ``1``, qC = ``1``; ` `    ``int` `oR = ``3``, oC = ``2``; ` `    ``if` `(canQueenAttack(qR, qC, oR, oC)) ` `        ``System.out.println(``"Yes"``); ` `    ``else` `        ``System.out.println(``"No"``); ` `} ` `} ` ` `  `// This code is Contributed by Code_Mech. `

## Python3

 `# Python3 implementation of the approach  ` ` `  `# Function that returns True if the  ` `# queen can attack the opponent  ` `def` `canQueenAttack(qR, qC, oR, oC):  ` ` `  `    ``# If queen and the opponent are ` `    ``# in the same row  ` `    ``if` `qR ``=``=` `oR: ` `        ``return` `True` ` `  `    ``# If queen and the opponent are  ` `    ``# in the same column  ` `    ``if` `qC ``=``=` `oC: ` `        ``return` `True` ` `  `    ``# If queen can attack diagonally  ` `    ``if` `abs``(qR ``-` `oR) ``=``=` `abs``(qC ``-` `oC):  ` `        ``return` `True` ` `  `    ``# Opponent is safe  ` `    ``return` `False` ` `  `# Driver code  ` `if` `__name__ ``=``=` `"__main__"``:  ` ` `  `    ``qR, qC ``=` `1``, ``1` `    ``oR, oC ``=` `3``, ``2` `    ``if` `canQueenAttack(qR, qC, oR, oC):  ` `        ``print``(``"Yes"``) ` `    ``else``: ` `        ``print``(``"No"``)  ` `     `  `# This code is contributed  ` `# by Rituraj Jain `

## C#

 `// C# implementation of the approach ` `using` `System; ` `class` `GFG ` `{ ` `     `  `// Function that returns true if the queen ` `// can attack the opponent ` `static` `bool` `canQueenAttack(``int` `qR, ``int` `qC, ` `                                ``int` `oR, ``int` `oC) ` `{ ` `    ``// If queen and the opponent ` `    ``// are in the same row ` `    ``if` `(qR == oR) ` `        ``return` `true``; ` ` `  `    ``// If queen and the opponent  ` `    ``// are in the same column ` `    ``if` `(qC == oC) ` `        ``return` `true``; ` ` `  `    ``// If queen can attack diagonally ` `    ``if` `(Math.Abs(qR - oR) == Math.Abs(qC - oC)) ` `        ``return` `true``; ` ` `  `    ``// Opponent is safe ` `    ``return` `false``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main() ` `{ ` `    ``int` `qR = 1, qC = 1; ` `    ``int` `oR = 3, oC = 2; ` `    ``if` `(canQueenAttack(qR, qC, oR, oC)) ` `        ``Console.WriteLine(``"Yes"``); ` `    ``else` `        ``Console.WriteLine(``"No"``); ` `} ` `} ` ` `  `// This code is Contributed by Code_Mech. `

## PHP

 ` `

Output:

```No
```

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