Programs to print Interesting Patterns

Program to print following pattern:
Examples :

Input : 5
Output: 
* * * * *  * * * * *
* * * *      * * * *
* * *          * * *
* *              * *
*                  *
*                  *
* *              * *
* * *          * * *
* * * *      * * * *
* * * * *  * * * * *

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

This program is divided into four parts.

C

// C program to print  
// the given pattern 
  
#include<stdio.h> 
pattern(int n) 
{ 
    int i,j; 
  
    // This is upper half of pattern 
    for (i=1; i<=n; i++) 
    { 
        for (j=1; j<=(2*n); j++) 
        { 
            // Left part of pattern 
            if (i>(n-j+1)) 
                printf(" "); 
            else
                printf("*"); 
                  
            // Right part of pattern 
            if ((i+n)>j) 
                printf(" "); 
            else
                printf("*"); 
        } 
        printf("\n"); 
    } 
      
    // This is lower half of pattern 
    for (i=1; i<=n; i++) 
    { 
        for (j=1; j<=(2*n); j++) 
        {  
            // Right Part of pattern 
            if (i<j) 
                printf(" "); 
            else
                printf("*"); 
              
            // Left Part of pattern 
            if (i<=((2*n)-j)) 
                printf(" "); 
            else
                printf("*"); 
        } 
        printf("\n"); 
    } 
} 
  
// main function 
int main() 
{ 
    pattern(7); 
    return 0; 
} 

Java

// Java program to print 
// the given pattern 
import java.io.*; 
  
class GFG { 
      
    static void pattern(int n) 
    { 
        int i, j; 
  
        // This is upper half of pattern 
        for (i = 1; i <= n; i++) { 
            for (j = 1; j <= (2 * n); j++) { 
                  
                // Left part of pattern 
                if (i > (n - j + 1)) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
  
                // Right part of pattern 
                if ((i + n) > j) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
            } 
              
            System.out.println(""); 
        } 
  
        // This is lower half of pattern 
        for (i = 1; i <= n; i++) { 
            for (j = 1; j <= (2 * n); j++) { 
                  
                // Right Part of pattern 
                if (i < j) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
  
                // Left Part of pattern 
                if (i <= ((2 * n) - j)) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
            } 
              
            System.out.println(""); 
        } 
    } 
  
    // main function 
    public static void main(String[] args) 
    { 
        pattern(7); 
    } 
} 
  
// This code is contributed by vt_m 

Python3

# Python3 program to print  
# the given pattern 
  
def pattern(n): 
      
    # This is upper half of pattern 
    for i in range (1, n + 1): 
        for j in range (1, 2 * n): 
              
            # Left part of pattern 
            if i > (n - j + 1): 
                print("", end = ' '); 
            else: 
                print("*", end = ''); 
                  
            # Right part of pattern 
            if i + n - 1 > j: 
                print("", end = ' '); 
            else: 
                print("*", end = ''); 
        print(""); 
          
    # This is lower half of pattern 
    for i in range (1, n + 1): 
        for j in range (1, 2 * n): 
            #Left part of pattern 
            if i < j: 
                print("", end = ' '); 
            else: 
                print("*", end = ''); 
                  
            # Right part of pattern 
            if i < 2 * n - j: 
                print("", end = ' '); 
            else: 
                print("*", end = ''); 
        print(""); 
          
# Driver Code 
pattern(7); 
  
# This code is contributed by mits 

C#

// C# program to print 
// the given pattern 
using System; 
  
class GFG 
{ 
    static void pattern(int n) 
    { 
        int i, j; 
  
        // This is upper 
        // half of pattern 
        for (i = 1; i <= n; i++)  
        { 
            for (j = 1; j <= (2 * n); j++)  
            { 
                  
                // Left part of pattern 
                if (i > (n - j + 1)) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
  
                // Right part of pattern 
                if ((i + n) > j) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
            } 
              
            Console.WriteLine(""); 
        } 
  
        // This is lower 
        // half of pattern 
        for (i = 1; i <= n; i++)  
        { 
            for (j = 1; j <= (2 * n); j++)  
            { 
                  
                // Right Part of pattern 
                if (i < j) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
  
                // Left Part of pattern 
                if (i <= ((2 * n) - j)) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
            } 
              
            Console.WriteLine(""); 
        } 
    } 
      
    // Driver Code 
    static public void Main () 
    { 
        pattern(7); 
    } 
} 
  
// This code is contributed by ajit 

PHP

<?php 
// PHP program to print  
// the given pattern 
  
function pattern($n) 
{ 
    $i; $j; 
  
    // This is upper half of pattern 
    for ($i = 1; $i <= $n; $i++) 
    { 
        for ($j = 1; $j <= (2 * $n); $j++) 
        { 
            // Left part of pattern 
            if ($i > ($n - $j + 1)) 
                echo " "; 
            else
                echo "*"; 
                  
            // Right part of pattern 
            if (($i + $n) > $j) 
                echo " "; 
            else
                echo "*"; 
        } 
        printf("\n"); 
    } 
      
    // This is lower half of pattern 
    for ($i = 1; $i <= $n; $i++) 
    { 
        for ($j = 1; $j <= (2 * $n); $j++) 
        {  
            // Right Part of pattern 
            if ($i < $j) 
                echo " "; 
            else
                echo "*"; 
              
            // Left Part of pattern 
            if ($i <= ((2 * $n) - $j)) 
                echo " "; 
            else
                echo "*"; 
        } 
        echo "\n"; 
    } 
} 
  
// Driver Code 
pattern(7); 
  
// This code is contributed by m_kit 
?> 

Output :


* * * * * * *  * * * * * * *
* * * * * *      * * * * * *
* * * * *          * * * * *
* * * *              * * * *
* * *                  * * *
* *                      * *
*                          *
*                          *
* *                      * *
* * *                  * * *
* * * *              * * * *
* * * * *          * * * * *
* * * * * *      * * * * * *
* * * * * * *  * * * * * * *

Program to print following pattern:
Examples :

Input : 5
Output: 
*                  *
* *              * *
* * *          * * *
* * * *      * * * *
* * * * *  * * * * *
* * * * *  * * * * *
* * * *      * * * *
* * *          * * *
* *              * *
*                  *

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

This program is divided into four parts.

C

// C program to print the  
// given pattern 
  
#include<stdio.h> 
pattern(int n) 
{ 
    int i,j; 
      
    // This is upper half of pattern 
    for (i=1; i<=n; i++) 
    { 
        for (j=1; j<=(2*n); j++) 
        { 
            // Left part of pattern 
            if (i<j) 
                printf(" "); 
            else
                printf("*"); 
              
            // Right part of pattern 
            if (i<=((2*n)-j)) 
                printf(" "); 
            else
                printf("*"); 
        } 
        printf("\n"); 
    } 
      
    // This is lower half of pattern 
    for (i=1; i<=n; i++) 
    { 
        for (j=1;j<=(2*n);j++) 
        { 
            // Left part of pattern 
            if (i>(n-j+1)) 
                printf(" "); 
            else
                printf("*"); 
                  
            // Right part of pattern 
            if ((i+n)>j) 
                printf(" "); 
            else
                printf("*"); 
        } 
        printf("\n"); 
    } 
} 
  
// main function 
int main() 
{ 
    pattern(7); 
    return 0; 
} 

Java

// Java program to print the 
// given pattern 
  
import java.io.*; 
  
class GFG { 
  
    static void pattern(int n) 
    { 
        int i, j; 
  
        // This is upper half of pattern 
        for (i = 1; i <= n; i++) { 
            for (j = 1; j <= (2 * n); j++) { 
                  
                // Left part of pattern 
                if (i < j) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
  
                // Right part of pattern 
                if (i <= ((2 * n) - j)) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
            } 
              
            System.out.println(""); 
        } 
  
        // This is lower half of pattern 
        for (i = 1; i <= n; i++) { 
            for (j = 1; j <= (2 * n); j++) { 
                  
                // Left part of pattern 
                if (i > (n - j + 1)) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
  
                // Right part of pattern 
                if ((i + n) > j) 
                    System.out.print(" "); 
                else
                    System.out.print("*"); 
            } 
              
            System.out.println(""); 
        } 
    } 
  
    // main function 
    public static void main(String[] args) 
    { 
        pattern(7); 
    } 
} 
  
// This code is contributed by vt_m 

Python3

# Python3 program to  
# print the given pattern 
  
def pattern(n): 
      
    # This is upper 
    # half of pattern 
    for i in range(1, n + 1): 
        for j in range(1, 2 * n + 1): 
              
            # Left part of pattern 
            if (i < j): 
                print("", end = " "); 
            else: 
                print("*", end = ""); 
                  
            # Right part of pattern 
            if (i <= ((2 * n) - j)): 
                print("", end = " "); 
            else: 
                print("*", end = ""); 
        print(""); 
      
    # This is lower  
    # half of pattern 
    for i in range(1, n + 1): 
        for j in range(1, 2 * n + 1): 
              
            # Left part of pattern 
            if (i > (n - j + 1)): 
                print("", end = " "); 
            else: 
                print("*", end = ""); 
              
            # Right part of pattern 
            if ((i + n) > j): 
                print("", end = " "); 
            else: 
                print("*", end = ""); 
        print(""); 
  
# Driver Code 
pattern(7); 
  
# This code is contributed 
# by mits 

C#

// C# program to print  
// the given pattern 
using System; 
  
class GFG 
{ 
    static void pattern(int n) 
    { 
        int i, j; 
  
        // This is upper  
        // half of pattern 
        for (i = 1; i <= n; i++) 
        { 
            for (j = 1; j <= (2 * n); j++)  
            { 
                  
                // Left part of pattern 
                if (i < j) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
  
                // Right part of pattern 
                if (i <= ((2 * n) - j)) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
            } 
              
            Console.WriteLine(""); 
        } 
  
        // This is lower 
        // half of pattern 
        for (i = 1; i <= n; i++)  
        { 
            for (j = 1; j <= (2 * n); j++)  
            { 
                  
                // Left part of pattern 
                if (i > (n - j + 1)) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
  
                // Right part of pattern 
                if ((i + n) > j) 
                    Console.Write(" "); 
                else
                    Console.Write("*"); 
            } 
              
            Console.WriteLine(""); 
        } 
    } 
  
    // Driver Code 
    static public void Main () 
    { 
        pattern(7); 
    } 
} 
  
// This code is contributed by ajit 

PHP

<?php 
// PHP program to print  
// the given pattern 
function pattern($n) 
{ 
    $i; $j; 
      
    // This is upper half 
    // of pattern 
    for ($i = 1; $i <= $n; $i++) 
    { 
        for ($j = 1; $j <= (2 * $n); $j++) 
        { 
            // Left part of pattern 
            if ($i < $j) 
                echo " "; 
            else
                echo "*"; 
              
            // Right part of pattern 
            if ($i <= ((2 * $n) - $j)) 
                echo " "; 
            else
                echo "*"; 
        } 
        echo "\n"; 
    } 
      
    // This is lower half of pattern 
    for ($i = 1; $i <= $n; $i++) 
    { 
        for ($j = 1;$j <= (2 * $n); $j++) 
        { 
            // Left part of pattern 
            if ($i > ($n - $j + 1)) 
                echo " "; 
            else
                echo "*"; 
                  
            // Right part of pattern 
            if (($i + $n) > $j) 
                echo " "; 
            else
                echo "*"; 
        } 
    echo "\n"; 
    } 
} 
  
// Driver Code 
pattern(7); 
  
// This code is contributed by aj_36 
?> 

Output :


*                          *
* *                      * *
* * *                  * * *
* * * *              * * * *
* * * * *          * * * * *
* * * * * *      * * * * * *
* * * * * * *  * * * * * * *
* * * * * * *  * * * * * * *
* * * * * *      * * * * * *
* * * * *          * * * * *
* * * *              * * * *
* * *                  * * *
* *                      * *
*                          *

This article is contributed by Aditya Kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C

Java

Python3

C#

PHP

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C

Java

Python3

C#

PHP

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