C program to traverse an Array

Given an integer array of size N, the task is to traverse and print the elements in the array.
Examples:

Input: arr[] = {2, -1, 5, 6, 0, -3} 
Output: 2 -1 5 6 0 -3

Input: arr[] = {4, 0, -2, -9, -7, 1} 
Output: 4 0 -2 -9 -7 1  

Approach:-

1. Start a loop from 0 to N-1, where N is the size of array. 

for(i = 0; i < N; i++)

2. Access every element of array with help of 

arr[index]

3. Print the elements. 

printf("%d ", arr[i])

Below is the implementation of the above approach:  

C

// C program to traverse the array

#include <stdio.h>

// Function to traverse and print the array
void printArray(int* arr, int n)
{
    int i;

    printf("Array: ");
    for (i = 0; i < n; i++) {
        printf("%d ", arr[i]);
    }
    printf("\n");
}

// Driver program
int main()
{
    int arr[] = { 2, -1, 5, 6, 0, -3 };
    int n = sizeof(arr) / sizeof(arr[0]);

    printArray(arr, n);

    return 0;
}

Output:

Array: 2 -1 5 6 0 -3

Time Complexity: O(n)  //since one traversal of the array is required to complete all operations hence overall time required by the algorithm is linear

Auxiliary Space: O(1)// since no extra array is used so the space taken by the algorithm is constant