We are given a matrix that contains different values in its each cell. Our aim is to find the minimal set of positions in the matrix such that entire matrix can be traversed starting from the positions in the set.
We can traverse the matrix under below conditions:
- We can move only to those neighbors that contain value less than or to equal to the current cell’s value. A neighbor of cell is defined as the cell that shares a side with the given cell.
Input : 1 2 3 2 3 1 1 1 1 Output : 1 1 0 2 If we start from 1, 1 we can cover 6 vertices in the order (1, 1) -> (1, 0) -> (2, 0) -> (2, 1) -> (2, 2) -> (1, 2). We cannot cover the entire matrix with this vertex. Remaining vertices can be covered (0, 2) -> (0, 1) -> (0, 0). Input : 3 3 1 1 Output : 0 1 If we start from 0, 1, we can traverse the entire matrix from this single vertex in this order (0, 0) -> (0, 1) -> (1, 1) -> (1, 0). Traversing the matrix in this order satisfies all the conditions stated above.
From the above examples, we can easily identify that in order to use minimum number of positions we have to start from the positions having highest cell value. Therefore we pick the positions that contain the highest value in the matrix. We take the vertices having highest value in separate array. We perform DFS on every vertex starting from the highest value. If we encounter any unvisited vertex during dfs then we have to include this vertex in our set. When all the cells have been processed then the set contains the required vertices.
How does this work?
We need to visit all vertices and to reach largest values we must start with them. If two largest values are not adjacent, then both of them must be picked. If two largest values are adjacent, then any of them can be picked as moving to equal value neighbors is allowed.
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- Minimum number of edges between two vertices of a graph using DFS
- Minimum Operations to make value of all vertices of the tree Zero
- Minimum number of edges between two vertices of a Graph
- Find K vertices in the graph which are connected to at least one of remaining vertices
- Shortest path to traverse all the elements of a circular array in increasing order
- Minimum cost to reach from the top-left to the bottom-right corner of a matrix
- Find the minimum number of moves needed to move from one cell of matrix to another
- Minimum steps required to convert X to Y where a binary matrix represents the possible conversions
- Count all possible paths between two vertices
- Articulation Points (or Cut Vertices) in a Graph
- Construct a graph from given degrees of all vertices
- Number of trees whose sum of degrees of all the vertices is L
- Shortest paths from all vertices to a destination
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Improved By : AjaySingh6