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Bottom View of a Binary Tree
  • Difficulty Level : Medium
  • Last Updated : 17 Dec, 2020

Given a Binary Tree, we need to print the bottom view from left to right. A node x is there in output if x is the bottommost node at its horizontal distance. Horizontal distance of left child of a node x is equal to horizontal distance of x minus 1, and that of right child is horizontal distance of x plus 1. 

Examples: 

                      20
                    /    \
                  8       22
                /   \      \
              5      3      25
                    / \      
                  10    14

For the above tree the output should be 5, 10, 3, 14, 25.
If there are multiple bottom-most nodes for a horizontal distance from root, then print the later one in level traversal. For example, in the below diagram, 3 and 4 are both the bottom-most nodes at horizontal distance 0, we need to print 4. 

                   
                      20
                    /    \
                  8       22
                /   \    /   \
              5      3 4     25
                    / \      
                  10    14

For the above tree the output should be 5, 10, 4, 14, 25. 

Method 1 – Using Queue 
The following are steps to print Bottom View of Binary Tree. 
1. We put tree nodes in a queue for the level order traversal. 
2. Start with the horizontal distance(hd) 0 of the root node, keep on adding left child to queue along with the horizontal distance as hd-1 and right child as hd+1. 
3. Also, use a TreeMap which stores key value pair sorted on key. 
4. Every time, we encounter a new horizontal distance or an existing horizontal distance put the node data for the horizontal distance as key. For the first time it will add to the map, next time it will replace the value. This will make sure that the bottom most element for that horizontal distance is present in the map and if you see the tree from beneath that you will see that element.



Below is the implementation of the above:

C++

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// C++ Program to print Bottom View of Binary Tree
#include<bits/stdc++.h>
using namespace std;
  
// Tree node class
struct Node
{
    int data; //data of the node
    int hd; //horizontal distance of the node
    Node *left, *right; //left and right references
  
    // Constructor of tree node
    Node(int key)
    {
        data = key;
        hd = INT_MAX;
        left = right = NULL;
    }
};
  
// Method that prints the bottom view.
void bottomView(Node *root)
{
    if (root == NULL)
        return;
  
    // Initialize a variable 'hd' with 0
    // for the root element.
    int hd = 0;
  
    // TreeMap which stores key value pair
    // sorted on key value
    map<int, int> m;
  
    // Queue to store tree nodes in level
    // order traversal
    queue<Node *> q;
  
    // Assign initialized horizontal distance
    // value to root node and add it to the queue.
    root->hd = hd;
    q.push(root);  // In STL, push() is used enqueue an item
  
    // Loop until the queue is empty (standard
    // level order loop)
    while (!q.empty())
    {
        Node *temp = q.front();
        q.pop();   // In STL, pop() is used dequeue an item
  
        // Extract the horizontal distance value
        // from the dequeued tree node.
        hd = temp->hd;
  
        // Put the dequeued tree node to TreeMap
        // having key as horizontal distance. Every
        // time we find a node having same horizontal
        // distance we need to replace the data in
        // the map.
        m[hd] = temp->data;
  
        // If the dequeued node has a left child, add
        // it to the queue with a horizontal distance hd-1.
        if (temp->left != NULL)
        {
            temp->left->hd = hd-1;
            q.push(temp->left);
        }
  
        // If the dequeued node has a right child, add
        // it to the queue with a horizontal distance
        // hd+1.
        if (temp->right != NULL)
        {
            temp->right->hd = hd+1;
            q.push(temp->right);
        }
    }
  
    // Traverse the map elements using the iterator.
    for (auto i = m.begin(); i != m.end(); ++i)
        cout << i->second << " ";
}
  
// Driver Code
int main()
{
    Node *root = new Node(20);
    root->left = new Node(8);
    root->right = new Node(22);
    root->left->left = new Node(5);
    root->left->right = new Node(3);
    root->right->left = new Node(4);
    root->right->right = new Node(25);
    root->left->right->left = new Node(10);
    root->left->right->right = new Node(14);
    cout << "Bottom view of the given binary tree :\n"
    bottomView(root);
    return 0;
}

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Java

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// Java Program to print Bottom View of Binary Tree
import java.util.*;
import java.util.Map.Entry;
  
// Tree node class
class Node
{
    int data; //data of the node
    int hd; //horizontal distance of the node
    Node left, right; //left and right references
  
    // Constructor of tree node
    public Node(int key)
    {
        data = key;
        hd = Integer.MAX_VALUE;
        left = right = null;
    }
}
  
//Tree class
class Tree
{
    Node root; //root node of tree
  
    // Default constructor
    public Tree() {}
  
    // Parameterized tree constructor
    public Tree(Node node)
    {
        root = node;
    }
  
    // Method that prints the bottom view.
    public void bottomView()
    {
        if (root == null)
            return;
  
        // Initialize a variable 'hd' with 0 for the root element.
        int hd = 0;
  
        // TreeMap which stores key value pair sorted on key value
        Map<Integer, Integer> map = new TreeMap<>();
  
         // Queue to store tree nodes in level order traversal
        Queue<Node> queue = new LinkedList<Node>();
  
        // Assign initialized horizontal distance value to root
        // node and add it to the queue.
        root.hd = hd;
        queue.add(root);
  
        // Loop until the queue is empty (standard level order loop)
        while (!queue.isEmpty())
        {
            Node temp = queue.remove();
  
            // Extract the horizontal distance value from the
            // dequeued tree node.
            hd = temp.hd;
  
            // Put the dequeued tree node to TreeMap having key
            // as horizontal distance. Every time we find a node
            // having same horizontal distance we need to replace
            // the data in the map.
            map.put(hd, temp.data);
  
            // If the dequeued node has a left child add it to the
            // queue with a horizontal distance hd-1.
            if (temp.left != null)
            {
                temp.left.hd = hd-1;
                queue.add(temp.left);
            }
            // If the dequeued node has a right child add it to the
            // queue with a horizontal distance hd+1.
            if (temp.right != null)
            {
                temp.right.hd = hd+1;
                queue.add(temp.right);
            }
        }
  
        // Extract the entries of map into a set to traverse
        // an iterator over that.
        Set<Entry<Integer, Integer>> set = map.entrySet();
  
        // Make an iterator
        Iterator<Entry<Integer, Integer>> iterator = set.iterator();
  
        // Traverse the map elements using the iterator.
        while (iterator.hasNext())
        {
            Map.Entry<Integer, Integer> me = iterator.next();
            System.out.print(me.getValue()+" ");
        }
    }
}
  
// Main driver class
public class BottomView
{
    public static void main(String[] args)
    {
        Node root = new Node(20);
        root.left = new Node(8);
        root.right = new Node(22);
        root.left.left = new Node(5);
        root.left.right = new Node(3);
        root.right.left = new Node(4);
        root.right.right = new Node(25);
        root.left.right.left = new Node(10);
        root.left.right.right = new Node(14);
        Tree tree = new Tree(root);
        System.out.println("Bottom view of the given binary tree:");
        tree.bottomView();
    }
}

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Python3

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# Python3 program to print Bottom
# View of Binary Tree
   
# Tree node class
class Node:
      
    def __init__(self, key):
          
        self.data = key
        self.hd = 1000000
        self.left = None
        self.right = None
   
# Method that prints the bottom view.
def bottomView(root):
  
    if (root == None):
        return
      
    # Initialize a variable 'hd' with 0
    # for the root element.
    hd = 0
      
    # TreeMap which stores key value pair
    # sorted on key value
    m = dict()
   
    # Queue to store tree nodes in level
    # order traversal
    q = []
   
    # Assign initialized horizontal distance
    # value to root node and add it to the queue.
    root.hd = hd
      
    # In STL, append() is used enqueue an item
    q.append(root)  
   
    # Loop until the queue is empty (standard
    # level order loop)
    while (len(q) != 0):
        temp = q[0]
          
        # In STL, pop() is used dequeue an item
        q.pop(0)  
          
        # Extract the horizontal distance value
        # from the dequeued tree node.
        hd = temp.hd
   
        # Put the dequeued tree node to TreeMap
        # having key as horizontal distance. Every
        # time we find a node having same horizontal
        # distance we need to replace the data in
        # the map.
        m[hd] = temp.data
   
        # If the dequeued node has a left child, add
        # it to the queue with a horizontal distance hd-1.
        if (temp.left != None):
            temp.left.hd = hd - 1
            q.append(temp.left)
   
        # If the dequeued node has a right child, add
        # it to the queue with a horizontal distance
        # hd+1.
        if (temp.right != None):
            temp.right.hd = hd + 1
            q.append(temp.right)
   
    # Traverse the map elements using the iterator.
    for i in sorted(m.keys()):
        print(m[i], end = ' ')
          
# Driver Code
if __name__=='__main__':
      
    root = Node(20)
    root.left = Node(8)
    root.right = Node(22)
    root.left.left = Node(5)
    root.left.right = Node(3)
    root.right.left = Node(4)
    root.right.right = Node(25)
    root.left.right.left = Node(10)
    root.left.right.right = Node(14)
      
    print("Bottom view of the given binary tree :")
      
    bottomView(root)
      
# This code is contributed by rutvik_56

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C#

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// C# program to print Bottom View of Binary Tree
using System;
using System.Collections;
using System.Collections.Generic;
   
// Tree node class
class Node
{
      
    // Data of the node
    public int data; 
      
    // Horizontal distance of the node
    public int hd; 
      
    // left and right references
    public Node left, right;
      
    // Constructor of tree node
    public Node(int key)
    {
        data = key;
        hd = 1000000;
        left = right = null;
    }
}
  
// Tree class
class Tree
{
      
    // Root node of tree
    Node root;
      
    // Default constructor
    public Tree(){}
      
    // Parameterized tree constructor
    public Tree(Node node)
    {
        root = node;
    }
   
    // Method that prints the bottom view.
    public void bottomView()
    {
        if (root == null)
            return;
              
        // Initialize a variable 'hd' with
        // 0 for the root element.
        int hd = 0;
   
        // TreeMap which stores key value
        // pair sorted on key value
        SortedDictionary<int,
                         int> map = new SortedDictionary<int,
                                                         int>();
   
        // Queue to store tree nodes in level order
        // traversal
        Queue queue = new Queue();
          
        // Assign initialized horizontal distance 
        // value to root node and add it to the queue.
        root.hd = hd;
        queue.Enqueue(root);
   
        // Loop until the queue is empty 
        // (standard level order loop)
        while (queue.Count != 0)
        {
            Node temp = (Node) queue.Dequeue();
   
            // Extract the horizontal distance value 
            // from the dequeued tree node.
            hd = temp.hd;
   
            // Put the dequeued tree node to TreeMap 
            // having key as horizontal distance.
            // Every time we find a node having same
            // horizontal distance we need to replace
            // the data in the map.
            map[hd] = temp.data;
   
            // If the dequeued node has a left child 
            // add it to the queue with a horizontal
            // distance hd-1.
            if (temp.left != null)
            {
                temp.left.hd = hd - 1;
                queue.Enqueue(temp.left);
            }
              
            // If the dequeued node has a right 
            // child add it to the queue with a
            // horizontal distance hd+1.
            if (temp.right != null)
            {
                temp.right.hd = hd + 1;
                queue.Enqueue(temp.right);
            }
        }
          
        foreach(int i in map.Values)
        {
            Console.Write(i + " ");
        }
    }
}
   
public class BottomView{
    
// Driver code
public static void Main(string[] args)
{
    Node root = new Node(20);
    root.left = new Node(8);
    root.right = new Node(22);
    root.left.left = new Node(5);
    root.left.right = new Node(3);
    root.right.left = new Node(4);
    root.right.right = new Node(25);
    root.left.right.left = new Node(10);
    root.left.right.right = new Node(14);
    Tree tree = new Tree(root);
      
    Console.WriteLine("Bottom view of the "
                      "given binary tree:");
      
    tree.bottomView();
}
}
  
// This code is contributed by pratham76

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Output: 

Bottom view of the given binary tree:
5 10 4 14 25

Method 2- Using HashMap() 
This method is contributed by Ekta Goel

Approach: 
Create a map like, map where key is the horizontal distance and value is a pair(a, b) where a is the value of the node and b is the height of the node. Perform a pre-order traversal of the tree. If the current node at a horizontal distance of h is the first we’ve seen, insert it in the map. Otherwise, compare the node with the existing one in map and if the height of the new node is greater, update in the Map.

Below is the implementation of the above:

C++

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// C++ Program to print Bottom View of Binary Tree
#include <bits/stdc++.h> 
#include <map>
using namespace std;
  
// Tree node class
struct Node 
{
    // data of the node
    int data;
      
    // horizontal distance of the node
    int hd; 
      
    //left and right references
    Node * left, * right; 
      
    // Constructor of tree node
    Node(int key) 
    {
        data = key;
        hd = INT_MAX;
        left = right = NULL;
    }
};
  
void printBottomViewUtil(Node * root, int curr, int hd, map <int, pair <int, int>> & m)
{
    // Base case
    if (root == NULL)
        return;
      
    // If node for a particular 
    // horizontal distance is not
    // present, add to the map.
    if (m.find(hd) == m.end()) 
    {
        m[hd] = make_pair(root -> data, curr);
    
    // Compare height for already 
    // present node at similar horizontal
    // distance
    else 
    {
        pair < int, int > p = m[hd];
        if (p.second <= curr)
        {
            m[hd].second = curr;
            m[hd].first = root -> data;
        }
    }
      
    // Recur for left subtree
    printBottomViewUtil(root -> left, curr + 1, hd - 1, m);
      
    // Recur for right subtree
    printBottomViewUtil(root -> right, curr + 1, hd + 1, m);
}
  
void printBottomView(Node * root) 
{
      
    // Map to store Horizontal Distance,
    // Height and Data.
    map < int, pair < int, int > > m;
      
    printBottomViewUtil(root, 0, 0, m);
      
     // Prints the values stored by printBottomViewUtil()
    map < int, pair < int, int > > ::iterator it;
    for (it = m.begin(); it != m.end(); ++it)
    {
        pair < int, int > p = it -> second;
        cout << p.first << " ";
    }
}
  
int main() 
{
    Node * root = new Node(20);
    root -> left = new Node(8);
    root -> right = new Node(22);
    root -> left -> left = new Node(5);
    root -> left -> right = new Node(3);
    root -> right -> left = new Node(4);
    root -> right -> right = new Node(25);
    root -> left -> right -> left = new Node(10);
    root -> left -> right -> right = new Node(14);
    cout << "Bottom view of the given binary tree :\n";
    printBottomView(root);
    return 0;
}

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Python3

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# Python3 program to print Bottom
# View of Binary Tree 
class Node:
      
    def __init__(self, key = None
                      left = None
                     right = None):
                           
        self.data = key
        self.left = left
        self.right = right
          
def printBottomView(root):
      
      # Create a dictionary where
    # key -> relative horizontal distance
    # of the node from root node and
    # value -> pair containing node's 
    # value and its level
    d = dict()
      
    printBottomViewUtil(root, d, 0, 0)
      
    # Traverse the dictionary in sorted 
    # order of their keys and print
    # the bottom view
    for i in sorted(d.keys()):
        print(d[i][0], end = " ")
  
def printBottomViewUtil(root, d, hd, level):
      
      # Base case
    if root is None:
        return
      
    # If current level is more than or equal 
    # to maximum level seen so far for the 
    # same horizontal distance or horizontal
    # distance is seen for the first time, 
    # update the dictionary
    if hd in d:
        if level >= d[hd][1]:
            d[hd] = [root.data, level]
    else:
        d[hd] = [root.data, level]
          
    # recur for left subtree by decreasing
    # horizontal distance and increasing
    # level by 1
    printBottomViewUtil(root.left, d, hd - 1
                                   level + 1)
      
    # recur for right subtree by increasing
    # horizontal distance and increasing 
    # level by 1
    printBottomViewUtil(root.right, d, hd + 1
                                    level + 1)
  
# Driver Code    
if __name__ == '__main__':
      
    root = Node(20)
    root.left = Node(8)
    root.right = Node(22
    root.left.left = Node(5
    root.left.right = Node(3
    root.right.left = Node(4
    root.right.right = Node(25
    root.left.right.left = Node(10
    root.left.right.right = Node(14
      
    print("Bottom view of the given binary tree :")
      
    printBottomView(root)
  
# This code is contributed by tusharroy

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