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Assigning multiple characters in an int in C language
• Difficulty Level : Hard
• Last Updated : 30 Apr, 2018

Consider the following C program.

 `#include ` `int` `main(``void``) ` `{ ` `    ``int` `a = ``'d'``; ` ` `  `    ``printf``(``"%d\n"``, a); ` `    ``/*OUTPUT - 100 (ASCII Code for character d)*/` ` `  `    ``int` `b = ``'dd'``; ` `    ``printf``(``"%d"``, b); ` `    ``/*OUTPUT - 25700 (Explanation in detail given below)*/` ` `  `    ``return` `0; ` `} `

Output :

```100
25700
```

We can easily guess that the output for ‘d’ is 100 as 100 is ASCII value of character ‘d’.

Let us consider below line

`int a = 'dd' `

(%d, a) prints 25700 as output
01100100 01100100 (Binary of 100 100)
Assuming int is of 2 bytes, starting byte is occupied by first character ‘d’ and second byte by second character ‘d’. Therefore overall binary involves 0110010001100100 i.e 2^14 + 2^13 + 2^10 + 2^6 + 2^5 + 2^2 = 25700.

Now guess the output of following code.

 `#include ` `int` `main(``void``) ` `{ ` `    ``int` `b = ``'de'``; ` `    ``printf``(``"%d"``, b); ` `    ``return` `0; ` `} `

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