The toArray() method of Java AbstractSequentialList is used to form an array of the same elements as that of the AbstractSequentialList. Basically, it copies all the element from a AbstractSequentialList to a new array.
Syntax:
Object[] arr = AbstractSequentialList.toArray()
Parameters: The method does not take any parameters.
Return Value: The method returns an array containing the elements similar to the AbstractSequentialList.
Below programs illustrate the AbstractSequentialList.toArray() method:
Program 1:
import java.util.*;
public class AbstractSequentialListDemo {
public static void main(String args[])
{
AbstractSequentialList<String>
abs_col = new LinkedList<String>();
abs_col.add( "Welcome" );
abs_col.add( "To" );
abs_col.add( "Geeks" );
abs_col.add( "For" );
abs_col.add( "Geeks" );
System.out.println( "The AbstractSequentialList: "
+ abs_col);
Object[] arr = abs_col.toArray();
System.out.println( "The array is:" );
for ( int j = 0 ; j < arr.length; j++)
System.out.println(arr[j]);
}
}
|
Output:
The AbstractSequentialList: [Welcome, To, Geeks, For, Geeks]
The array is:
Welcome
To
Geeks
For
Geeks
Program 2:
import java.util.*;
public class AbstractSequentialListDemo {
public static void main(String args[])
{
AbstractSequentialList<Integer>
abs_col = new LinkedList<Integer>();
abs_col.add( 10 );
abs_col.add( 15 );
abs_col.add( 30 );
abs_col.add( 20 );
abs_col.add( 5 );
abs_col.add( 25 );
System.out.println( "The AbstractSequentialList: "
+ abs_col);
Object[] arr = abs_col.toArray();
System.out.println( "The array is:" );
for ( int j = 0 ; j < arr.length; j++)
System.out.println(arr[j]);
}
}
|
Output:
The AbstractSequentialList: [10, 15, 30, 20, 5, 25]
The array is:
10
15
30
20
5
25
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