AbstractSequentialList toArray() method in Java with Example
The toArray() method of Java AbstractSequentialList is used to form an array of the same elements as that of the AbstractSequentialList. Basically, it copies all the element from a AbstractSequentialList to a new array.
Syntax:
Object[] arr = AbstractSequentialList.toArray()
Parameters: The method does not take any parameters.
Return Value: The method returns an array containing the elements similar to the AbstractSequentialList.
Below programs illustrate the AbstractSequentialList.toArray() method:
Program 1:
import java.util.*;
public class AbstractSequentialListDemo {
public static void main(String args[])
{
AbstractSequentialList<String>
abs_col = new LinkedList<String>();
abs_col.add( "Welcome" );
abs_col.add( "To" );
abs_col.add( "Geeks" );
abs_col.add( "For" );
abs_col.add( "Geeks" );
System.out.println( "The AbstractSequentialList: "
+ abs_col);
Object[] arr = abs_col.toArray();
System.out.println( "The array is:" );
for ( int j = 0 ; j < arr.length; j++)
System.out.println(arr[j]);
}
}
|
Output:
The AbstractSequentialList: [Welcome, To, Geeks, For, Geeks]
The array is:
Welcome
To
Geeks
For
Geeks
Program 2:
import java.util.*;
public class AbstractSequentialListDemo {
public static void main(String args[])
{
AbstractSequentialList<Integer>
abs_col = new LinkedList<Integer>();
abs_col.add( 10 );
abs_col.add( 15 );
abs_col.add( 30 );
abs_col.add( 20 );
abs_col.add( 5 );
abs_col.add( 25 );
System.out.println( "The AbstractSequentialList: "
+ abs_col);
Object[] arr = abs_col.toArray();
System.out.println( "The array is:" );
for ( int j = 0 ; j < arr.length; j++)
System.out.println(arr[j]);
}
}
|
Output:
The AbstractSequentialList: [10, 15, 30, 20, 5, 25]
The array is:
10
15
30
20
5
25
Last Updated :
24 Dec, 2018
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