AbstractSequentialList lastIndexOf() method in Java with Example
The lastIndexOf() method of java.util.AbstractSequentialList class is used to return the index of the first occurrence of the specified element in this list, or -1 if this list does not contain the element. More formally, returns the lowest index i such that (o==null ? get(i)==null : o.equals(get(i))), or -1 if there is no such index.
Syntax:
public int lastIndexOf(Object o)
Parameters: This method takes Object o as parameter which is the element to search for.
Return Value: This method returns the index of the first occurrence of the specified element in this list, or -1 if this list does not contain the element.
Exception: This method throws:
- ClassCastException: if the type of the specified element is incompatible with this list.
- NullPointerException: if the specified element is null and this list does not permit null elements.
Below are the examples to illustrate the lastIndexOf() method.
Example 1:
import java.util.*;
public class GFG {
public static void main(String[] args)
{
AbstractSequentialList<Integer>
arrlist1 = new LinkedList<Integer>();
arrlist1.add( 10 );
arrlist1.add( 20 );
arrlist1.add( 30 );
arrlist1.add( 40 );
arrlist1.add( 50 );
System.out.println( "AbstractSequentialList: "
+ arrlist1);
int index = arrlist1.lastIndexOf( 30 );
System.out.println( "Last Index of 30: "
+ index);
}
}
|
Output:
AbstractSequentialList: [10, 20, 30, 40, 50]
Last Index of 30: 2
Example 2:
import java.util.*;
public class GFG1 {
public static void main(String[] args)
{
AbstractSequentialList<Integer>
arrlist1 = new LinkedList<Integer>();
arrlist1.add( 10 );
arrlist1.add( 20 );
arrlist1.add( 30 );
arrlist1.add( 40 );
arrlist1.add( 50 );
System.out.println( "LinkedListlist: "
+ arrlist1);
int index = arrlist1.lastIndexOf( 100 );
System.out.println( "Last Index of 100: "
+ index);
}
}
|
Output:
LinkedListlist: [10, 20, 30, 40, 50]
Last Index of 100: -1
Last Updated :
24 Dec, 2018
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