AbstractSequentialList toArray() method in Java with Example
The toArray() method of Java AbstractSequentialList is used to form an array of the same elements as that of the AbstractSequentialList. Basically, it copies all the element from a AbstractSequentialList to a new array.
Syntax:
Object[] arr = AbstractSequentialList.toArray()
Parameters: The method does not take any parameters.
Return Value: The method returns an array containing the elements similar to the AbstractSequentialList.
Below programs illustrate the AbstractSequentialList.toArray() method:
Program 1:
// Java code to illustrate toArray() import java.util.*; public class AbstractSequentialListDemo { public static void main(String args[]) { // Creating an empty AbstractSequentialList AbstractSequentialList<String> abs_col = new LinkedList<String>(); // Use add() method to add // elements into the AbstractSequentialList abs_col.add( "Welcome" ); abs_col.add( "To" ); abs_col.add( "Geeks" ); abs_col.add( "For" ); abs_col.add( "Geeks" ); // Displaying the AbstractSequentialList System.out.println( "The AbstractSequentialList: " + abs_col); // Creating the array and using toArray() Object[] arr = abs_col.toArray(); System.out.println( "The array is:" ); for ( int j = 0 ; j < arr.length; j++) System.out.println(arr[j]); } } |
The AbstractSequentialList: [Welcome, To, Geeks, For, Geeks] The array is: Welcome To Geeks For Geeks
Program 2:
// Java code to illustrate toArray() import java.util.*; public class AbstractSequentialListDemo { public static void main(String args[]) { // Creating an empty AbstractSequentialList AbstractSequentialList<Integer> abs_col = new LinkedList<Integer>(); // Use add() method to add // elements into the AbstractSequentialList abs_col.add( 10 ); abs_col.add( 15 ); abs_col.add( 30 ); abs_col.add( 20 ); abs_col.add( 5 ); abs_col.add( 25 ); // Displaying the AbstractSequentialList System.out.println( "The AbstractSequentialList: " + abs_col); // Creating the array and using toArray() Object[] arr = abs_col.toArray(); System.out.println( "The array is:" ); for ( int j = 0 ; j < arr.length; j++) System.out.println(arr[j]); } } |
The AbstractSequentialList: [10, 15, 30, 20, 5, 25] The array is: 10 15 30 20 5 25
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