GeeksforGeeks App
Open App
Browser
Continue

# Wind Energy Formula

The method of using wind to generate electricity is known as wind energy. The kinetic energy in the wind is converted into mechanical power by wind turbines.

Wind energy is a renewable energy source that determines the wind’s entire power. Wind turbines convert kinetic energy to mechanical power, which is then transformed into electricity, which is then used as a source of energy.

### Wind Energy Formula

P = 1/2ρAv3

Where,

ρ = Density  (kg/m3)

A = Swept Area  (m2)

v = Wind Speed  (m/s)

P = Power (W)

Derivation of Wind Energy Formula

The kinetic energy of an item with mass m and velocity v under constant acceleration is equal to the work done W in displacing that object from its original position.

Under a force F, rest to a distance s, i.e.

E = W = Fs

According to Newton’s Law, we have:

F = ma

Hence,

E = mas … (1)

Using the third equation of motion:

v2 = u2 + 2as

we get:

a = (v2 – u2)/2s

Since the initial velocity of the object is zero, i.e.

u = 0 , we get:

a = v2/2s

Substituting it in equation (1), we get that the

kinetic energy of a mass in motions is:

E = 1/2mv2……….(2)

The power in the wind is given by the rate of

change of energy:

P = dE/dt = 1/2v2dm/dt ……..(3)

As mass flow rate is given by:

and the rate of change of distance is given by:

dx/dt = v

we get:

dm/dt = ρAv

Hence, from equation (3), the power can be

defined as:

P = 1/2ρAv3

### Sample Problems

Problem 1: If the wind speed is 20 m/s and the blade length is 50 m, calculate the power in the wind.

Solution:

Given:

Wind speed v = 20 m/s,

Blade length l = 50 m,

Air density ρ = 1.23 kg/m.

The area is given by, A = πr2

A = π × 2500= 7850 m2

The wind power formula is given as,

P = 1/2ρAV3

P = 1/2 x (1.23) x (7850) x 203

P = 38622 W

Problem 2: A wind turbine has a blade length of 20 metres and runs at a speed of 10 metres per second. Determine the amount of wind power available.

Solution:

Given:

Wind speed v =10 m/s,

Blade length l = 20 m,

air density ρ = 1.23 kg/m3,

area , A = πr2

= π × 400

= 1256 m2

The wind power formula is given as,

P = 1/2ρAV3

= 0.5 × 1.23 × 1256 × 1000

P = 772440 W.

Problem 3: Calculate the wind power. Given:

Blade length, l = 22 m

Average Island Wind speed, v = 10 m/sec

Air Density, ρ = 1.23 kg/m3

Solution:

Area, A = πr

= π x 484

= 1520.5 m2

The wind energy formula is given by,

P = 1/2ρAV3

= 1/2 x (1.23) x (1520.5) x 103

P = 935107.5 W

Problem 4: Determine a realistic power output (in megawatts) for your client that the wind turbine could deliver.

Blade length, l = 22 m

Average Island Wind speed, v = 10 m/sec

Air Density, ρ = 1.23 kg/m3

Ct = 40% (Turbine efficiency rating)

Ca = 65% (Alternator/Generator efficiency rating)

Solution:

P = 1/2 x ρ x A x v3 x Ct x Ca

P = 1/2 x 1.23 kg/m3 x (π x 222) x (10m/sec)3 x 0.4 x 0.65

P = 0.24 MW

Problem 5: The actual available power from a wind mill with diameter 1 m, efficiency 0.2 (20%) – with wind velocity 10 m/s

Solution:

P   = 1/2ρAV3

Pa = (0.2) x (1.2 kg/m3) x π x (1 m)2 x (10 m/s)3 / 8

= 94.2 W

My Personal Notes arrow_drop_up
Related Tutorials