# What is 6y to the power of -4?

Mathematics is not only about numbers but it is about dealing with different calculations involving numbers and variables. This is what basically is known as Algebra. Algebra is defined as the representation of calculations involving mathematical expressions that consist of numbers, operators, and variables. Numbers can be from 0 to 9, operators are the mathematical operators like +, -, Ã—, Ã·, exponents, etc, variables like x, y, z, etc.

### Exponents and Powers

Exponents and powers are the basic operators used in mathematical calculations, exponents are used to simplify the complex calculations involving multiple self multiplications, self multiplications are basically numbers multiplied by themselves. For example, 7 Ã— 7 Ã— 7 Ã— 7 Ã— 7, can be simply written as 75. Here, 7 is the base value and 5 is the exponent and the value is 16807. 11 Ã— 11 Ã— 11, can be written as 113, here, 11 is the base value and 3 is the exponent or power of 11. The value of 113 is 1331.

Exponent is defined as the power given to a number, the number of times it is multiplied by itself. If an expression is written as cxy where c is a constant, c will be the coefficient, x is the base and y is the exponent. If a number say p, is multiplied n times, n will be the exponent of p. It will be written as

p Ã— p Ã— p Ã— p … n times = pn

### Basic rules of Exponents

There are certain basic rules defined for exponents in order to solve the exponential expressions along with the other mathematical operations, for example, if there are the product of two exponents, it can be simplified to make the calculation easier and is known as product rule, let’s look at some of the basic rules of exponents,

• Product Rule â‡¢ an Ã— am = an + m
• Quotient Rule â‡¢ an / am = an – m
• Power Rule â‡¢ (an)m = an Ã— m or mâˆšan = an/m
• Negative Exponent Rule â‡¢ a-m = 1/am
• Zero Rule â‡¢ a0 = 1
• One Rule â‡¢ a1 = a

### What is 6y to the power of -4?

Solution:

As it is clearly seen, the entire problem statement is asking for a simplification using exponent rules, looking at the expression (6y)-4, it is observed that the exponent -4 is the exponent for both 6 and y, therefore, simply apply the power for both 6 and y,

(6y)-4 = (6)-4 Ã— y-4

Using negative exponent rule, a-m = 1/am

= 1/(64y4)

= 1/(1296y4)

Therefore, 1/(1296y4) is the value obtained.

### Similar Problems

Question 1: Simplify 90(y2)5

Solution:

It is observed that 2 is the exponent of y and 5 is the exponent of y2, and 90 is constant, using the power rule of exponents, it can be written as,

Power Rule â‡¢ (an)m = an Ã— m

90(y2)5 = 90y(2 Ã— 5)

= 90y10

Question 2: Simplify 5(ex)2

Solution:

As it is clearly seen, the entire problem statement is asking for a simplification using exponent rules, looking at the expression 5(ex)2, it is observed that x is the exponent of e and 2 is the exponent of ex, and 5 is constant, using the power rule of exponents, it can be written as,

Power Rule â‡¢ (an)m = an Ã— m

5(ex)2 = 5(ex Ã— 2)

= 5(e2x)

Question 3: Simplify 30(y6)0

Solution:

It is observed that 6 is the exponent of y and 0 is the exponent of y6, and 30 is constant, using the power rule of exponents, it can be written as,

Power Rule â‡¢ (an)m = an Ã— m

30(y6)0 = 30(y6 Ã— 0)

Applying Zero Rule â‡¢  a0 = 1

= 30(1) = 30

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