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Traversing a map (or unordered_map) in C++ STL
  • Difficulty Level : Basic
  • Last Updated : 23 Sep, 2017

We can traverse map and unordered_map using following different ways.

Using a range based for loop

map

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// CPP program to traverse a map using range 
// based for loop
#include <bits/stdc++.h>
using namespace std;
  
int main()
{
    int arr[] = { 1, 1, 2, 1, 1, 3, 4, 3 };
    int n = sizeof(arr) / sizeof(arr[0]);
  
    map<int, int> m;
    for (int i = 0; i < n; i++)
        m[arr[i]]++;
  
    cout << "Element  Frequency" << endl;
    for (auto i : m)
        cout << i.first << "   " << i.second 
             << endl;
  
    return 0;
}

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unordered_map

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// CPP program to traverse a unordered_map using 
// range based for loop
#include <bits/stdc++.h>
using namespace std;
  
int main()
{
    int arr[] = { 1, 1, 2, 1, 1, 3, 4, 3 };
    int n = sizeof(arr) / sizeof(arr[0]);
  
    unordered_map<int, int> m;
    for (int i = 0; i < n; i++)
        m[arr[i]]++;
  
    cout << "Element Frequency" << endl;
    for (auto i : m)
        cout << i.first << "    " << i.second
             << endl;
  
    return 0;
}

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Output [NOTE: For unordered_map output rows can be
in any order]

Element  Frequency
1        4
2        1
3        2
4        1

 

Traversing using begin() and end()



map

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// CPP program to traverse a map using iterators
#include <bits/stdc++.h>
using namespace std;
  
int main()
{
    int arr[] = { 1, 1, 2, 1, 1, 3, 4, 3 };
    int n = sizeof(arr) / sizeof(arr[0]);
  
    map<int, int> m;
    for (int i = 0; i < n; i++)
        m[arr[i]]++;
  
    cout << " Element Frequency" << endl;
    for (auto i = m.begin(); i != m.end(); i++)
        cout << i->first << "      " << i->second
             << endl;
  
    return 0;
}

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unordered_map

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// CPP program to traverse a unordered_map 
// using iterators
#include <bits/stdc++.h>
using namespace std;
  
int main()
{
    int arr[] = { 1, 1, 2, 1, 1, 3, 4, 3 };
    int n = sizeof(arr) / sizeof(arr[0]);
  
    unordered_map<int, int> m;
    for (int i = 0; i < n; i++)
        m[arr[i]]++;
  
    cout << " Element Frequency" << endl;
    for (auto i = m.begin(); i != m.end(); i++)
        cout << i->first << "       " << i->second 
             << endl;
  
    return 0;
}

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Output [NOTE: For unordered_map output rows can be
in any order]

Element  Frequency
1        4
2        1
3        2
4        1

This article is contributed by Kartik. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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