Skip to content
Related Articles

Related Articles

StrictMath floor() Method in Java

View Discussion
Improve Article
Save Article
Like Article
  • Difficulty Level : Basic
  • Last Updated : 13 Dec, 2021

The java.lang.StrictMath.floor() is the inbuilt method which returns the largest double value, less than or equal to the given argument and is equal to the integer value. 

  • The result is the same as the argument when the given argument is equal to the integer.
  • The result is the same as the argument when the given argument is NaN, infinity, positive zero or negative zero.

Syntax :  

public static double floor(double num)

Parameters: This method accepts one parameter num which is of double type .
Return Value : The method returns the largest value which, closest to positive infinity, less than or equal to the argument and equal to an integer.
Examples :  

Input: num = 9.6
Output: 9.0

Input: num = -7.8
Output: -8.0

Below programs illustrate the java.lang.StrictMath.floor() method: 
Program 1:  

java




// Java program to illustrate the
//java.lang.StrictMath.floor()
 
import java.lang.*;
 
public class Geeks {
 
public static void main(String[] args) {
 
    double num1 = 7.8, num2 = 1.4 ;
 
    double fValue = StrictMath.floor(num1);
    System.out.println("The floor value of "+
                             num1+" = " + fValue);
 
    fValue = StrictMath.floor(num2);
    System.out.println("The floor value of "+
                             num2+" = " + fValue);
}
}

Output: 

The floor value of 7.8 = 7.0
The floor value of 1.4 = 1.0

 

Program2: 

java




// Java program to illustrate the
//java.lang.StrictMath.floor()
 
import java.lang.*;
 
public class Geeks {
 
public static void main(String[] args) {
 
    double num1 = -7.8, num2 = -1.4 ,num3 = 0.1 ;
 
    double fValue = StrictMath.floor(num1);
    System.out.println("The floor value of "+
                             num1+" = " + fValue);
 
    fValue = StrictMath.floor(num2);
    System.out.println("The floor value of "+
                             num2+" = " + fValue);
 
    fValue = StrictMath.floor(num3);
    System.out.println("The floor value of "+
                             num3+" = " + fValue);
 
}
}

Output: 

The floor value of -7.8 = -8.0
The floor value of -1.4 = -2.0
The floor value of 0.1 = 0.0

 


My Personal Notes arrow_drop_up
Recommended Articles
Page :

Start Your Coding Journey Now!