# StrictMath IEEEremainder() Method in Java

The Java.lang.StrictMath.IEEEremainder() is an inbuilt method of StrictMath class which is used to perform the remainder operation on given two arguments as prescribed by the IEEE 754 standard. The remainder value is mathematically equal to , where rem is the mathematical integer closest to exact mathematical value of the quotient , and when two mathematical integers are equally close to , and n is an even integer. It gives rise to two special results:

• Its sign is same as the sign of the first argument when the remainder is zero.
• It returns NaN when either argument is NaN, or num1 is infinite, or num2 is positive or negative zero.
• The result is same as the num1 when num1 is finite and the num2 is infinite.

Syntax:

`public static double IEEEremainder(double num1, double num2)`

Parameters: The method accepts two parameters :

• num1: This is of double type which is the dividend.
• num2 This is als of double type which is the divisor.

Return Value: The method returns the remainder when num1 is divided by num2.

Examples :

```Input:
num1 = 100.61d
num2 = 5.32d

Output: -0.47000000000000597
```

Below programs illustrate the Java.lang.StrictMath.IEEEremainder() method:
Program 1:

 `// Java praogram to illustrate the ` `// Java.lang.StrictMath.IEEEremainder() ` `import` `java.lang.*; ` ` `  `public` `class` `Geeks { ` ` `  `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` ` `  `        ``double` `num1 = ``5651``.51d, num2 = ``61``.79d; ` ` `  `        ``// It  returns the remainder value ` `        ``double` `remain_val = StrictMath.IEEEremainder(num1, num2); ` `        ``System.out.println(``"Remainder value of "``+num1+``" & "``+num2 ` `                                            ``+``" = "` `+ remain_val); ` `    ``} ` `} `

Output:

```Remainder value of 5651.51 & 61.79 = 28.620000000000296
```

Program 2:

 `// Java praogram to illustrate the ` `// Java.lang.StrictMath.IEEEremainder() ` `import` `java.lang.*; ` ` `  `public` `class` `Geeks { ` ` `  `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``/* Here  num1 is finite and num2 is infinite so  ` `     ``the result is the same as the num1 */` `        ``double` `num1 = ``70``.55d, num2 = (``1.0``) / (``0.0``); ` ` `  `        ``double` `remain_val = StrictMath.IEEEremainder(num1, num2); ` `        ``System.out.println(``"Remainder value of "``+num1+``" & "``+num2 ` `                                            ``+``" = "` `+ remain_val); ` `    ``} ` `} `

Output:

```Remainder value is = 70.55
```

My Personal Notes arrow_drop_up lets make it a lil simple

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