Sort the given matrix

Given a n x n matrix. The problem is to sort the given matrix in strict order. Here strict order means that matrix is sorted in a way such that all elements in a row are sorted in increasing order and for row ‘i’, where 1 <= i <= n-1, first element of row 'i' is greater than or equal to the last element of row 'i-1'.

Examples:

Input : mat[][] = { {5, 4, 7},
                    {1, 3, 8},
                    {2, 9, 6} }
Output : 1 2 3
         4 5 6
         7 8 9



Approach: Create a temp[] array of size n^2. Starting with the first row one by one copy the elements of the given matrix into temp[]. Sort temp[]. Now one by one copy the elements of temp[] back to the given matrix.

C++

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// C++ implementation to sort the given matrix
#include <bits/stdc++.h>
using namespace std;
  
#define SIZE 10
  
// function to sort the given matrix
void sortMat(int mat[SIZE][SIZE], int n)
{
    // temporary matrix of size n^2
    int temp[n * n];
    int k = 0;
  
    // copy the elements of matrix one by one
    // into temp[]
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
            temp[k++] = mat[i][j];
  
    // sort temp[]
    sort(temp, temp + k);
      
    // copy the elements of temp[] one by one
    // in mat[][]
    k = 0;
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
            mat[i][j] = temp[k++];
}
  
// function to print the given matrix
void printMat(int mat[SIZE][SIZE], int n)
{
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++)
            cout << mat[i][j] << " ";
        cout << endl;
    }
}
  
// Driver program to test above
int main()
{
    int mat[SIZE][SIZE] = { { 5, 4, 7 },
                            { 1, 3, 8 },
                            { 2, 9, 6 } };
    int n = 3;
  
    cout << "Original Matrix:\n";
    printMat(mat, n);
  
    sortMat(mat, n);
  
    cout << "\nMatrix After Sorting:\n";
    printMat(mat, n);
  
    return 0;
}

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Java














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// Java implementation to  


// sort the given matrix 


import java.io.*; 


import java.util.*; 


  


class GFG { 


      


    static int SIZE = 10; 


  


    // function to sort the given matrix 


    static void sortMat(int mat[][], int n) 


    { 


        // temporary matrix of size n^2 


        int temp[] = new int[n * n]; 


        int k = 0; 


      


        // copy the elements of matrix  


        // one by one into temp[] 


        for (int i = 0; i < n; i++) 


            for (int j = 0; j < n; j++) 


                temp[k++] = mat[i][j]; 


      


        // sort temp[] 


        Arrays.sort(temp); 


          


        // copy the elements of temp[] 


        // one by one in mat[][] 


        k = 0; 


        for (int i = 0; i < n; i++) 


            for (int j = 0; j < n; j++) 


                mat[i][j] = temp[k++]; 


    } 


      


    // function to print the given matrix 


    static void printMat(int mat[][], int n) 


    { 


        for (int i = 0; i < n; i++) { 


            for (int j = 0; j < n; j++) 


                System.out.print( mat[i][j] + " "); 


            System.out.println(); 


        } 


    } 


      


    // Driver program to test above 


    public static void main(String args[]) 


    { 


        int mat[][] = { { 5, 4, 7 }, 


                        { 1, 3, 8 }, 


                        { 2, 9, 6 } }; 


        int n = 3; 


      


        System.out.println("Original Matrix:"); 


        printMat(mat, n); 


      


        sortMat(mat, n); 


      


        System.out.println("Matrix After Sorting:"); 


        printMat(mat, n); 


      


    } 


} 


  


// This code is contributed by Nikita Tiwari. 



















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Python3














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# Python3 implementation to sort 


# the given matrix 


  


SIZE = 10


  


# Function to sort the given matrix 


def sortMat(mat, n) : 


      


    # Temporary matrix of size n^2 


    temp = [0] * (n * n) 


    k = 0


  


    # Copy the elements of matrix   


    # one by one into temp[] 


    for i in range(0, n) : 


          


        for j in range(0, n) : 


              


            temp[k] = mat[i][j] 


            k += 1


  


    # sort temp[] 


    temp.sort() 


      


    # copy the elements of temp[]  


    # one by one in mat[][] 


    k = 0


      


    for i in range(0, n) : 


          


        for j in range(0, n) : 


            mat[i][j] = temp[k] 


            k += 1


  


  


# Function to print the given matrix 


def printMat(mat, n) : 


      


    for i in range(0, n) : 


          


        for j in range( 0, n ) : 


              


            print(mat[i][j] , end = " ") 


              


        print() 


      


      


# Driver program to test above 


mat = [ [ 5, 4, 7 ], 


        [ 1, 3, 8 ], 


        [ 2, 9, 6 ] ] 


n = 3


  


print( "Original Matrix:") 


printMat(mat, n) 


  


sortMat(mat, n) 


  


print("\nMatrix After Sorting:") 


printMat(mat, n) 


  


  


# This code is contributed by Nikita Tiwari. 



















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C#














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// C# implementation to 


// sort the given matrix 


using System; 


  


class GFG { 


    static int SIZE = 10; 


  


    // function to sort the given matrix 


    static void sortMat(int[, ] mat, int n) 


    { 


        // temporary matrix of size n^2 


        int[] temp = new int[n * n]; 


        int k = 0; 


  


        // copy the elements of matrix 


        // one by one into temp[] 


        for (int i = 0; i < n; i++) 


            for (int j = 0; j < n; j++) 


                temp[k++] = mat[i, j]; 


  


        // sort temp[] 


        Array.Sort(temp); 


  


        // copy the elements of temp[] 


        // one by one in mat[][] 


        k = 0; 


        for (int i = 0; i < n; i++) 


            for (int j = 0; j < n; j++) 


            mat[i, j] = temp[k++]; 


    } 


  


    // function to print the given matrix 


    static void printMat(int[, ] mat, int n) 


    { 


        for (int i = 0; i < n; i++) { 


            for (int j = 0; j < n; j++) 


            Console.Write(mat[i, j] + " "); 


            Console.WriteLine(); 


        } 


    } 


  


    // Driver code 


    public static void Main() 


    { 


        int[, ] mat = { { 5, 4, 7 }, 


                        { 1, 3, 8 }, 


                        { 2, 9, 6 } }; 


        int n = 3; 


  


        Console.WriteLine("Original Matrix:"); 


        printMat(mat, n); 


  


        sortMat(mat, n); 


  


        Console.WriteLine("Matrix After Sorting:"); 


        printMat(mat, n); 


    } 


} 


  


// This code is contributed by Sam007 



















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Output :


Original Matrix:
5 4 7
1 3 8
2 9 6

Matrix After Sorting:
1 2 3
4 5 6
7 8 9



Time Complexity: O(n2log2n).

Auxiliary Space: O(n2).



          
          
          

          

    

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    Article Tags : 
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Sorting

           	
Practice Tags : 
Sorting
Matrix

        

         

         
 
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