Smallest Even number with N digits

Given a number N, the task is to find the smallest Even number with N digits.

Examples:

Input: N = 1
Output: 0

Input: N = 2
Output: 10 

Approach:
Case 1 : If N = 1 then answer will be 0.
Case 2 : if N != 1 then answer will be (10^(N-1)) because the series of smallest even numbers will go on like, 0, 10, 100, 1000, 10000, 100000, …..



Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to return smallest even
// number with n digits
int smallestEven(int n)
{
    if (n == 1)
        return 0;
    return pow(10, n - 1);
}
  
// Driver Code
int main()
{
  
    int n = 4;
    cout << smallestEven(n);
  
    return 0;
}

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Java

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// Java implementation of the approach
class Solution {
  
    // Function to return smallest even
    // number with n digits
    static int smallestEven(int n)
    {
        if (n == 1)
            return 0;
        return Math.pow(10, n - 1);
    }
  
    // Driver code
    public static void main(String args[])
    {
        int n = 4;
        System.out.println(smallestEven(n));
    }
}

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Python3

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# Python3 implementation of 
# the approach
  
# Function to return smallest 
# even number with n digits
def smallestEven(n) :
  
    if (n == 1):
        return 0
    return pow(10, n - 1)
  
# Driver Code
n = 4
print(smallestEven(n))
  
# This code is contributed 
# by ihritik.

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C#

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// C# implementation of the approach
using System;
class Solution {
  
    // Function to return smallest even
    // number with n digits
    static int smallestEven(int n)
    {
        if (n == 1)
            return 0;
        return Math.pow(10, n - 1);
    }
  
    // Driver code
    public static void Main()
    {
        int n = 4;
        Console.Write(smallestEven(n));
    }
}

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PHP

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<?php
// PHP implementation of the approach
  
// Function to return smallest 
// even number with n digits
function smallestEven($n)
{
    if ($n == 1)
        return 0;
    return pow(10, $n - 1);
}
  
// Driver Code
$n = 4;
echo smallestEven($n);
  
// This code is contributed 
// by ihritik.
?>

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Output:

1000

Time Complexity: O(1).



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Improved By : ihritik