# Ruby | Integer upto() function

The times function in Ruby returns all the numbers from a given to number itself. It iterates the given block, passing in increasing values from number1 up to number2. If no block is given, an Enumerator is returned instead.

Syntax: (number1).upto(number2)

Parameter: The function takes number1 and number2 which is the range in which the numbers are returned. It also takes a block.

Return Value: The function returns all the numbers from number1 to number2 itself.

Example 1:

 `#Ruby program for upto() function ` ` `  `#Initializing the number ` `num1 = 8 num2 = 12 ` ` `  `#Prints the number from num1 to num2 ` `                ``puts` `num1.upto(num2) ` `{ ` `    ``| i | print i, ``" "` `} ` ` `  `#Initializing the number ` `num3 = 5 num4 = 15 ` ` `  `#Prints the number from num3 to num4 ` `                ``puts` `num3.upto(num4) ` `{ ` `    ``| i | print i, ``" "` `} `

Output:

```8 9 10 11 12 8
5 6 7 8 9 10 11 12 13 14 15 5
```

Example 2:

 `#Ruby program for upto() function ` ` `  `#Initializing the number ` `num1 = 1 num2 = 3 ` ` `  `#Prints the number from num1 to num2 ` `                ``puts` `num1.upto(num2) ` `{ ` `    ``| i | print i, ``" "` `} ` ` `  `#Initializing the number ` `num3 = -7 num4 = -2 ` ` `  `#Prints the number from num3 to num4 ` `                  ``puts` `num3.upto(num4) ` `{ ` `    ``| i | print i, ``" "` `} `

Output:

```1 2 3 1
-7 -6 -5 -4 -3 -2 -7
```

Example 3:

 `#Ruby program for upto() function ` ` `  `#Initializing the number ` `num1 = 1 num2 = 3 ` ` `  `#Returns an enumerator ` `#since no block is passed ` `                ``puts` `num1.upto(num2) `

Output:

```#
```

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