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Ruby | Integer upto() function
• Last Updated : 04 Dec, 2020

The upto function in Ruby returns all the numbers from a given to number itself. It iterates the given block, passing in increasing values from number1 up to number2. If no block is given, an Enumerator is returned instead.

Syntax: (number1).upto(number2)

Parameter: The function takes number1 and number2 which is the range in which the numbers are returned. It also takes a block.

Return Value: The function returns all the numbers from number1 to number2 itself.

Example 1

Ruby

 `#Ruby program for upto() function`   `#Initializing the number` `num1 = ``8` `num2 = ``12`   `#Prints the number from num1 to num2` `                ``puts num1.upto(num2)` `{` `    ``| i | print i, ``" "` `}`   `#Initializing the number` `num3 = ``5` `num4 = ``15`   `#Prints the number from num3 to num4` `                ``puts num3.upto(num4)` `{` `    ``| i | print i, ``" "` `}`

Output

```8 9 10 11 12 8
5 6 7 8 9 10 11 12 13 14 15 5```

Example 2

Ruby

 `#Ruby program for upto() function`   `#Initializing the number` `num1 = ``1` `num2 = ``3`   `#Prints the number from num1 to num2` `                ``puts num1.upto(num2)` `{` `    ``| i | print i, ``" "` `}`   `#Initializing the number` `num3 = -``7` `num4 = -``2`   `#Prints the number from num3 to num4` `                  ``puts num3.upto(num4)` `{` `    ``| i | print i, ``" "` `}`

Output

```1 2 3 1
-7 -6 -5 -4 -3 -2 -7```

Example 3

Ruby

 `#Ruby program for upto() function`   `#Initializing the number` `num1 = ``1` `num2 = ``3`   `#Returns an enumerator` `#since no block is passed` `                ``puts num1.upto(num2)`

Output

`#`

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