Ruby | Integer upto() function

The times function in Ruby returns all the numbers from a given to number itself. It iterates the given block, passing in increasing values from number1 up to number2. If no block is given, an Enumerator is returned instead.

Syntax: (number1).upto(number2)

Parameter: The function takes number1 and number2 which is the range in which the numbers are returned. It also takes a block.



Return Value: The function returns all the numbers from number1 to number2 itself.

Example 1:

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#Ruby program for upto() function
  
#Initializing the number
num1 = 8 num2 = 12
  
#Prints the number from num1 to num2
                puts num1.upto(num2)
{
    | i | print i, " "
}
  
#Initializing the number
num3 = 5 num4 = 15
  
#Prints the number from num3 to num4
                puts num3.upto(num4)
{
    | i | print i, " "
}

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Output:

8 9 10 11 12 8
5 6 7 8 9 10 11 12 13 14 15 5

Example 2:

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#Ruby program for upto() function
  
#Initializing the number
num1 = 1 num2 = 3
  
#Prints the number from num1 to num2
                puts num1.upto(num2)
{
    | i | print i, " "
}
  
#Initializing the number
num3 = -7 num4 = -2
  
#Prints the number from num3 to num4
                  puts num3.upto(num4)
{
    | i | print i, " "
}

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Output:

1 2 3 1
-7 -6 -5 -4 -3 -2 -7

Example 3:

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#Ruby program for upto() function
  
#Initializing the number
num1 = 1 num2 = 3
  
#Returns an enumerator
#since no block is passed
                puts num1.upto(num2)

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Output:

#

Reference: https://devdocs.io/ruby~2.5/integer#method-i-upto



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