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Remove repeated digits in a given number
• Difficulty Level : Easy
• Last Updated : 27 Apr, 2021

Given an integer, remove consecutive repeated digits from it.
Examples:

```Input: x = 12224
Output: 124

Input: x = 124422
Output: 1242

Input: x = 11332
Output: 132```

We need to process all digits of n and remove consecutive representations. We can go through all digits by repeatedly dividing n with 10 and taking n%10.

## C++

 `// C++ program to remove repeated digits``#include ``using` `namespace` `std;` `long` `int` `removeRecur(``long` `int` `n)``{``    ``// Store first digits as previous digit``    ``int` `prev_digit = n % 10;` `    ``// Initialize power``    ``long` `int` `pow` `= 10;``    ``long` `int` `res = prev_digit;` `    ``// Iterate through all digits of n, note that``    ``// the digits are processed from least significant``    ``// digit to most significant digit.``    ``while` `(n) {``        ``// Store current digit``        ``int` `curr_digit = n % 10;` `        ``if` `(curr_digit != prev_digit) {``            ``// Add the current digit to the beginning``            ``// of result``            ``res += curr_digit * ``pow``;` `            ``// Update previous result and power``            ``prev_digit = curr_digit;``            ``pow` `*= 10;``        ``}` `        ``// Remove last digit from n``        ``n = n / 10;``    ``}` `    ``return` `res;``}` `// Driver program``int` `main()``{``    ``long` `int` `n = 12224;``    ``cout << removeRecur(n);``    ``return` `0;``}`

## Java

 `// Java program to remove repeated digits``import` `java.io.*;` `class` `GFG {` `    ``static` `long` `removeRecur(``long` `n)``    ``{``        ` `        ``// Store first digits as previous``        ``// digit``        ``long` `prev_digit = n % ``10``;``    ` `        ``// Initialize power``        ``long` `pow = ``10``;``        ``long` `res = prev_digit;``    ` `        ``// Iterate through all digits of n,``        ``// note that the digits are``        ``// processed from least significant``        ``// digit to most significant digit.``        ``while` `(n>``0``) {``            ` `            ``// Store current digit``            ``long` `curr_digit = n % ``10``;``    ` `            ``if` `(curr_digit != prev_digit)``            ``{``                ``// Add the current digit to``                ``// the beginning of result``                ``res += curr_digit * pow;``    ` `                ``// Update previous result``                ``// and power``                ``prev_digit = curr_digit;``                ``pow *= ``10``;``            ``}``    ` `            ``// Remove last digit from n``            ``n = n / ``10``;``        ``}``    ` `        ``return` `res;``    ``}``    ` `    ``// Driver program``    ``public` `static` `void` `main (String[] args)``    ``{``        ``long` `n = ``12224``;``        ` `        ``System.out.println(removeRecur(n));``    ``}``}` `// This code is contributed by anuj_67.`

## Python3

 `# Python 3 program to remove repeated digits` `def` `removeRecur(n):``    ` `    ``# Store first digits as previous digit``    ``prev_digit ``=` `n ``%` `10` `    ``# Initialize power``    ``pow` `=` `10``    ``res ``=` `prev_digit` `    ``# Iterate through all digits of n, note``    ``# that the digits are processed from``    ``# least significant digit to most``    ``# significant digit.``    ``while` `(n):``        ` `        ``# Store current digit``        ``curr_digit ``=` `n ``%` `10` `        ``if` `(curr_digit !``=` `prev_digit):``            ` `            ``# Add the current digit to the``            ``# beginning of result``            ``res ``+``=` `curr_digit ``*` `pow` `            ``# Update previous result and power``            ``prev_digit ``=` `curr_digit``            ``pow` `*``=` `10` `        ``# Remove last digit from n``        ``n ``=` `int``(n ``/` `10``)``    ` `    ``return` `res` `# Driver Code``if` `__name__ ``=``=` `'__main__'``:``    ``n ``=` `12224``    ``print``(removeRecur(n))` `# This code is contributed by``# Surendra_Gangwar`

## C#

 `// C# program to remove repeated digits``using` `System;` `class` `GFG {` `    ``static` `long` `removeRecur(``long` `n)``    ``{``        ` `        ``// Store first digits as previous``        ``// digit``        ``long` `prev_digit = n % 10;``    ` `        ``// Initialize power``        ``long` `pow = 10;``        ``long` `res = prev_digit;``    ` `        ``// Iterate through all digits of n,``        ``// note that the digits are``        ``// processed from least significant``        ``// digit to most significant digit.``        ``while` `(n > 0) {``            ` `            ``// Store current digit``            ``long` `curr_digit = n % 10;``    ` `            ``if` `(curr_digit != prev_digit)``            ``{``                ``// Add the current digit to``                ``// the beginning of result``                ``res += curr_digit * pow;``    ` `                ``// Update previous result``                ``// and power``                ``prev_digit = curr_digit;``                ``pow *= 10;``            ``}``    ` `            ``// Remove last digit from n``            ``n = n / 10;``        ``}``    ` `        ``return` `res;``    ``}``    ` `    ``// Driver program``    ``public` `static` `void` `Main ()``    ``{``        ``long` `n = 12224;``        ` `        ``Console.WriteLine(removeRecur(n));``    ``}``}` `// This code is contributed by anuj_67.`

## PHP

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## Javascript

 ``

Output:

`124`