Given a string Str, the task is to remove first adjacent pairs of similar characters until we can.
Note: Remove adjacent characters to get a new string and then again remove adjacent duplicates from the new string and keep repeating this process until all similar adjacent character pairs are removed.
Input: str = “keexxllx”
Step 0: Remove ee to get “kxxllx”
Step 1: Remove xx to get “kllx”
Step 2: Remove ll to get “kx”
Input: str = “abbaca”
Use string’s back() and pop_back() method STL in C++ to solve the above problem. Iterate for every character in the string, and if the adjacent characters are same, then remove the adjacent characters using pop_back() function. At the end, return the final string.
Below is the implementation of the above approach:
- Rearrange the characters of the string such that no two adjacent characters are consecutive English alphabets
- Permutation of a string with maximum number of characters greater than its adjacent characters
- String with k distinct characters and no same characters adjacent
- Minimum swaps to group similar characters side by side?
- Recursively remove all adjacent duplicates
- Rearrange characters in a string such that no two adjacent are same
- Rearrange characters in a string such that no two adjacent are same using hashing
- Count of strings where adjacent characters are of difference one
- Count of adjacent Vowel Consonant Pairs
- Minimum replacements to make adjacent characters unequal in a ternary string | Set-2
- Minimum replacements to make adjacent characters unequal in a ternary string
- Remove characters that appear more than k times
- Remove even frequency characters from the string
- Remove all characters other than alphabets from string
- Remove all non-alphabetical characters of a String in Java
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Improved By : AnkitRai01