# Python | Triple Product to K

The problem of getting the product number of pairs that lead to a particular solution has been dealt many times, this articles aims at extending that to 3 numbers and discussing several ways in which this particular problem can be solved. Let’s discuss certain ways in which this can be performed.

Method #1 : Using Nested loops
This is the naive method in which this particular problem can be solved and takes outer loop to iterate for each elements and inner loop checks for the remaining difference multiplying the pairs to the result.

 `# Python3 code to demonstrate ` `# 3 element product ` `# using nested loops ` ` `  `# initializing list ` `test_list ``=` `[``4``, ``1``, ``3``, ``2``, ``6``, ``12``] ` ` `  `# initializing product ` `product ``=` `24` ` `  `# printing original list ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# using nested loops ` `# 3 element product ` `res ``=` `[] ` `for` `i ``in` `range``(``0``, ``len``(test_list)``-``2``): ` `    ``for` `j ``in` `range``(i ``+` `1``, ``len``(test_list)``-``1``): ` `        ``for` `k ``in` `range``(j ``+` `1``, ``len``(test_list)): ` `            ``if` `test_list[i] ``*` `test_list[j] ``*` `test_list[k] ``=``=` `product: ` `                ``temp ``=` `[] ` `                ``temp.append(test_list[i]) ` `                ``temp.append(test_list[j]) ` `                ``temp.append(test_list[k]) ` `                ``res.append(``tuple``(temp)) ` ` `  `# print result ` `print``(``"The 3 product element list is : "` `+` `str``(res)) `

Output :

```The original list : [4, 1, 3, 2, 6, 12]
The 3 product element list is : [(4, 1, 6), (4, 3, 2), (1, 2, 12)]
```

Method #2 : Using `itertools.combination()`
This particular problem can also be done in a concise manner using the inbuilt function of function. The combination function finds all the combination taking K arguments leading to particular product.

 `# Python3 code to demonstrate ` `# Triple Product to K ` `# using itertools.combination() ` `from` `itertools ``import` `combinations ` ` `  `# function to get the product ` `def` `test(val): ` `    ``prod ``=` `1`  `    ``for` `ele ``in` `val: ` `        ``prod ``*``=` `ele ` `    ``return` `(prod ``=``=` `24``) ` `     `  `# initializing list ` `test_list ``=` `[``4``, ``1``, ``3``, ``2``, ``6``, ``12``] ` ` `  `# initializing product ` `product ``=` `24` ` `  `# printing original list ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# using itertools.combination() ` `# 3 element product  ` `res ``=` `list``(``filter``(test, ``list``(combinations(test_list, ``3``)))) ` ` `  `# print result ` `print``(``"The 3 product element list is : "` `+` `str``(res)) `

Output :

```The original list : [4, 1, 3, 2, 6, 12]
The 3 product element list is : [(4, 1, 6), (4, 3, 2), (1, 2, 12)]
```

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