# Python | Triple list difference

The difference between 2 lists have been dealt previously, but sometimes, we can have more than two lists and we need to find the mutual differences of one list with every other list. This kind of problem has applications in many domains. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using `map() + set()` + list comprehension

The combination of above 3 functions can be used to perform this particular task. The map function can be used to convert the list to set by the set function and list comprehension can be used to get the new mutual difference list for each list.

 `# Python3 code to demonstrate ` `# triple list difference  ` `# using map() + set() + list comprehension ` ` `  `# initializing lists  ` `test_list1 ``=` `[``1``, ``5``, ``6``, ``4``, ``7``] ` `test_list2 ``=` `[``8``, ``4``, ``3``] ` `test_list3 ``=` `[``9``, ``10``, ``3``, ``5``] ` ` `  `# printing original lists ` `print``(``"The original list 1 : "` `+` `str``(test_list1)) ` `print``(``"The original list 2 : "` `+` `str``(test_list2)) ` `print``(``"The original list 3 : "` `+` `str``(test_list3)) ` ` `  `# using map() + set() + list comprehension ` `# triple list difference  ` `temp1, temp2, temp3 ``=` `map``(``set``, (test_list1, test_list2, test_list3)) ` `res1 ``=` `[ele ``for` `ele ``in` `test_list1 ``if` `ele ``not` `in` `temp2 ``and` `ele ``not` `in` `temp3] ` `res2 ``=` `[ele ``for` `ele ``in` `test_list2 ``if` `ele ``not` `in` `temp1 ``and` `ele ``not` `in` `temp3] ` `res3 ``=` `[ele ``for` `ele ``in` `test_list3 ``if` `ele ``not` `in` `temp2 ``and` `ele ``not` `in` `temp1] ` ` `  `# print result ` `print``(``"The mutual difference list are : "` `      ``+` `str``(res1) ``+` `" "` `+` `str``(res2) ``+` `" "` `+` `str``(res3)) `

Output :

```The original list 1 : [1, 5, 6, 4, 7]
The original list 2 : [8, 4, 3]
The original list 3 : [9, 10, 3, 5]
The mutual difference list are : [1, 6, 7]  [9, 10]
```

Method #2 : Using` map() + set() + "-"` operator

This problem can also be solved the minus operator, if one wishes not to use the list comprehension. The minus operator can perform the boolean match difference to compute the valid set difference.

 `# Python3 code to demonstrate ` `# triple list difference  ` `# using map() + set() + "-" operator ` ` `  `# initializing lists  ` `test_list1 ``=` `[``1``, ``5``, ``6``, ``4``, ``7``] ` `test_list2 ``=` `[``8``, ``4``, ``3``] ` `test_list3 ``=` `[``9``, ``10``, ``3``, ``5``] ` ` `  `# printing original lists ` `print``(``"The original list 1 : "` `+` `str``(test_list1)) ` `print``(``"The original list 2 : "` `+` `str``(test_list2)) ` `print``(``"The original list 3 : "` `+` `str``(test_list3)) ` ` `  `# using map() + set() + "-" operator ` `# triple list difference  ` `temp1, temp2, temp3 ``=` `map``(``set``, (test_list1, test_list2, test_list3)) ` `res1 ``=` `temp1 ``-` `temp2 ``-` `temp3 ` `res2 ``=` `temp2 ``-` `temp3 ``-` `temp1 ` `res3 ``=` `temp3 ``-` `temp1 ``-` `temp2 ` `res1, res2, res3 ``=` `map``(``list``, (res1, res2, res3)) ` ` `  `# print result ` `print``(``"The mutual difference list are : "` `      ``+` `str``(res1) ``+` `" "` `+` `str``(res2) ``+` `" "` `+` `str``(res3)) `

Output :

```The original list 1 : [1, 5, 6, 4, 7]
The original list 2 : [8, 4, 3]
The original list 3 : [9, 10, 3, 5]
The mutual difference list are : [1, 6, 7]  [9, 10]
```

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