Given a list of strings, write a Python program to split the list into sublists based on string length.

**Examples:**

Input :['The', 'art', 'of', 'programming']Output :[['of'], ['The', 'art'], ['programming']]Input :['Welcome', 'to', 'geeksforgeeks']Output :[['to'], ['Welcome'], ['geeksforgeeks']]

**Approach #1 :** Pythonic naive

A naive approach for the above method uses a dictionary and a for loop to traverse the list. In each iteration, it checks whether the element length is already in the list or not. If not, it adds the element length and element as `key:value`

pair, otherwise, the element is just added to the value sublist. Finally, we make a list of all the values of the dict and return it.

`# Python3 program to Divide list of strings ` `# into sublists based on string length` ` ` `def` `divideList(lst):` ` ` `dct ` `=` `{}` ` ` ` ` `for` `element ` `in` `lst:` ` ` `if` `len` `(element) ` `not` `in` `dct:` ` ` `dct[` `len` `(element)] ` `=` `[element]` ` ` `elif` `len` `(element) ` `in` `dct:` ` ` `dct[` `len` `(element)] ` `+` `=` `[element]` ` ` ` ` `res ` `=` `[]` ` ` `for` `key ` `in` `sorted` `(dct):` ` ` `res.append(dct[key])` ` ` ` ` `return` `res` ` ` `# Driver code` `lst ` `=` `[` `'The'` `, ` `'art'` `, ` `'of'` `, ` `'programming'` `]` `print` `(divideList(lst))` |

**Output:**

[['of'], ['The', 'art'], ['programming']]

**Approach #2 : **`defaultdict()`

from collections module

This method uses *defaultdict* and saves it in a variable ‘group_by_len’. Using a for loop, we save the length of string as key and the string with the key length as its value. Finally, we make a list of all the values of ‘group_by_len’ and return it.

`# Python3 program to Divide list of strings ` `# into sublists based on string length` `from` `collections ` `import` `defaultdict` ` ` `def` `divideList(lst):` ` ` `group_by_len ` `=` `defaultdict(` `list` `)` ` ` `for` `ele ` `in` `lst:` ` ` `group_by_len[` `len` `(ele)].append(ele)` ` ` ` ` `res ` `=` `[]` ` ` `for` `key ` `in` `sorted` `(group_by_len):` ` ` `res.append(group_by_len[key])` ` ` ` ` `return` `res` ` ` `# Driver code` `lst ` `=` `[` `'The'` `, ` `'art'` `, ` `'of'` `, ` `'programming'` `]` `print` `(divideList(lst))` |

**Output:**

[['of'], ['The', 'art'], ['programming']]

**Approach #3 : **`groupby()`

from *itertools* module

The most efficient and simplest method to solve the given problem is using `groupby()`

from *itertools* module. This is a one-liner where we use two vaiables ‘l'(for length) and ‘g'(group of strings) to traverse through ‘lst’, grouped by length and finally return all groups packed within a list.

`# Python3 program to Divide list of strings ` `# into sub lists based on string length` `from` `itertools ` `import` `groupby` ` ` `def` `divideList(lst):` ` ` `res ` `=` `dict` `((l, ` `list` `(g)) ` `for` `l, g ` `in` `groupby(lst, key ` `=` `len` `))` ` ` ` ` `# Sorting dict by key` ` ` `res ` `=` `sorted` `(res.items(), key ` `=` `lambda` `kv:(kv[` `0` `], kv[` `1` `]))` ` ` ` ` `# Removing key from list of tuple` ` ` `return` `[el[` `1` `:] ` `for` `el ` `in` `(` `tuple` `(x) ` `for` `x ` `in` `res)]` ` ` `# Driver code` `lst ` `=` `[` `'The'` `, ` `'art'` `, ` `'of'` `, ` `'programming'` `]` `print` `(divideList(lst))` |

**Output:**

[(['of'],), (['The', 'art'],), (['programming'],)]

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