Given a Dictionary, sort by summation of key and value.
Input : test_dict = {3:5, 1:3, 4:6, 2:7, 8:1}
Output : {1: 3, 3: 5, 2: 7, 8: 1, 4: 6}
Explanation : 4 < 8 < 9 = 9 < 10 are increasing summation of keys and values.
Input : test_dict = {3:5, 1:3, 4:6, 2:7}
Output : {1: 3, 3: 5, 2: 7, 4: 6}
Explanation : 4 < 8 < 9 < 10 are increasing summation of keys and values.
Method : Using sorted() + lambda + items()
In this sort operation is performed using sorted(), lambda function is used to provide addition logic. The items() is used to get both keys and values.
Python3
# Python3 code to demonstrate working of # Sort Dictionary by key-value Summation # Using sorted() + lambda + items() # initializing dictionary test_dict = {3: 5, 1: 3, 4: 6, 2: 7, 8: 1} # printing original dictionary print("The original dictionary is : " + str(test_dict)) # sorted() to sort, lambda provides key-value addition res = sorted(test_dict.items(), key=lambda sub: sub[0] + sub[1]) # converting to dictionary res = {sub[0]: sub[1] for sub in res} # printing result print("The sorted result : " + str(res)) |
Output:
The original dictionary is : {3: 5, 1: 3, 4: 6, 2: 7, 8: 1}
The sorted result : {1: 3, 3: 5, 2: 7, 8: 1, 4: 6}
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