# Python – Sort Dictionary by key-value Summation

• Last Updated : 12 Nov, 2020

Given a Dictionary, sort by summation of key and value.

Input : test_dict = {3:5, 1:3, 4:6, 2:7, 8:1}
Output : {1: 3, 3: 5, 2: 7, 8: 1, 4: 6}
Explanation : 4 < 8 < 9 = 9 < 10 are increasing summation of keys and values.

Input : test_dict = {3:5, 1:3, 4:6, 2:7}
Output : {1: 3, 3: 5, 2: 7, 4: 6}
Explanation : 4 < 8 < 9 < 10 are increasing summation of keys and values.

Method : Using sorted() + lambda + items()

In this sort operation is performed using sorted(), lambda function is used to provide addition logic. The items() is used to get both keys and values.

## Python3

 `# Python3 code to demonstrate working of``# Sort Dictionary by key-value Summation``# Using sorted() + lambda + items()`` ` `# initializing dictionary``test_dict ``=` `{``3``: ``5``, ``1``: ``3``, ``4``: ``6``, ``2``: ``7``, ``8``: ``1``}`` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# sorted() to sort, lambda provides key-value addition``res ``=` `sorted``(test_dict.items(), key``=``lambda` `sub: sub[``0``] ``+` `sub[``1``])`` ` `# converting to dictionary``res ``=` `{sub[``0``]: sub[``1``] ``for` `sub ``in` `res}`` ` `# printing result``print``(``"The sorted result : "` `+` `str``(res))`

Output:

```The original dictionary is : {3: 5, 1: 3, 4: 6, 2: 7, 8: 1}
The sorted result : {1: 3, 3: 5, 2: 7, 8: 1, 4: 6}```
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