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Python – Sort Dictionary by key-value Summation
  • Last Updated : 12 Nov, 2020

Given a Dictionary, sort by summation of key and value. 

Input : test_dict = {3:5, 1:3, 4:6, 2:7, 8:1} 
Output : {1: 3, 3: 5, 2: 7, 8: 1, 4: 6} 
Explanation : 4 < 8 < 9 = 9 < 10 are increasing summation of keys and values.
 

Input : test_dict = {3:5, 1:3, 4:6, 2:7} 
Output : {1: 3, 3: 5, 2: 7, 4: 6} 
Explanation : 4 < 8 < 9 < 10 are increasing summation of keys and values. 

Method : Using sorted() + lambda + items()

In this sort operation is performed using sorted(), lambda function is used to provide addition logic. The items() is used to get both keys and values.



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# Python3 code to demonstrate working of
# Sort Dictionary by key-value Summation
# Using sorted() + lambda + items()
  
# initializing dictionary
test_dict = {3: 5, 1: 3, 4: 6, 2: 7, 8: 1}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# sorted() to sort, lambda provides key-value addition
res = sorted(test_dict.items(), key=lambda sub: sub[0] + sub[1])
  
# converting to dictionary
res = {sub[0]: sub[1] for sub in res}
  
# printing result
print("The sorted result : " + str(res))

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Output:

The original dictionary is : {3: 5, 1: 3, 4: 6, 2: 7, 8: 1}
The sorted result : {1: 3, 3: 5, 2: 7, 8: 1, 4: 6}

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