# Python – Remove Consecutive K element records

Sometimes, while working with Python records, we can have a problem in which we need to remove records on the basis of presence of consecutive K elements in tuple. This kind of problem is peculiar but can have applications in data domains. Let’s discuss certain ways in which this task can be performed.

Input :
test_list = [(4, 5), (5, 6), (1, 3), (0, 0)]
K = 0
Output : [(4, 5), (5, 6), (1, 3)]

Input :
test_list = [(4, 5), (5, 6), (1, 3), (5, 4)]
K = 5
Output : [(4, 5), (5, 6), (1, 3), (5, 4)]

Method #1 : Using `zip()` + list comprehension
The combination of above functions can be used to solve this problem. In this, we need to combine two consecutive segments using zip() and perform the comparison in list comprehension.

 `# Python3 code to demonstrate working of  ` `# Remove Consecutive K element records ` `# Using zip() + list comprehension ` ` `  `# initializing list ` `test_list ``=` `[(``4``, ``5``, ``6``, ``3``), (``5``, ``6``, ``6``, ``9``), (``1``, ``3``, ``5``, ``6``), (``6``, ``6``, ``7``, ``8``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing K  ` `K ``=` `6` ` `  `# Remove Consecutive K element records ` `# Using zip() + list comprehension ` `res ``=` `[idx ``for` `idx ``in` `test_list ``if` `(K, K) ``not` `in` `zip``(idx, idx[``1``:])] ` ` `  `# printing result  ` `print``(``"The records after removal : "` `+` `str``(res))  `

Output :

```The original list is : [(4, 5, 6, 3), (5, 6, 6, 9), (1, 3, 5, 6), (6, 6, 7, 8)]
The records after removal : [(4, 5, 6, 3), (1, 3, 5, 6)]
```

Method #2 : Using `any()` + list comprehension
The combination of above functions can be used to solve this problem. In this, we check for consecutive elements using any() and list comprehension is used to remake the list.

 `# Python3 code to demonstrate working of  ` `# Remove Consecutive K element records ` `# Using any() + list comprehension ` ` `  `# initializing list ` `test_list ``=` `[(``4``, ``5``, ``6``, ``3``), (``5``, ``6``, ``6``, ``9``), (``1``, ``3``, ``5``, ``6``), (``6``, ``6``, ``7``, ``8``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing K  ` `K ``=` `6` ` `  `# Remove Consecutive K element records ` `# Using any() + list comprehension ` `res ``=` `[idx ``for` `idx ``in` `test_list ``if` `not` `any``(idx[j] ``=``=` `K ``and` `idx[j ``+` `1``] ``=``=` `K ``for` `j ``in` `range``(``len``(idx) ``-` `1``))] ` ` `  `# printing result  ` `print``(``"The records after removal : "` `+` `str``(res))  `

Output :

```The original list is : [(4, 5, 6, 3), (5, 6, 6, 9), (1, 3, 5, 6), (6, 6, 7, 8)]
The records after removal : [(4, 5, 6, 3), (1, 3, 5, 6)]
```

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