Given a list. The task is to print the largest even and largest odd number in a list.
Examples:
Input: 1 3 5 8 6 10 Output: Largest even number is 10 Largest odd number is 5 Input: 123 234 236 694 809 Output: Largest odd number is 809 Largest even number is 694
The first approach uses two methods , one for computing largest even number and the other for computing the largest odd number in a list of numbers, input by the user. Each of the methods prints the largest even and odd number respectively. We maintain one counter for each method, for current largest even or odd and check if the number is divisible by two or not . Accordingly, we print the largest values.
Python3
class LargestOddAndEven: # find largest even number of # the list def largestEven(self, list): # counter for current largest # even number curr = -1 for num in list: # converting number to integer # explicitly num = int(num) # even number is divisible by 2 and # if larger than current largest if(num % 2 == 0 and num > curr): # replace current largest even curr = num print("Largest even number is ", curr) # find largest odd number of the list def largestOdd(self, list): # current largest odd number currO = -1 for num in list: # converting number to integer # explicitly num = int(num) # even number is divisible by 2 and # if larger than current largest if(num % 2 == 1 and num > currO): # replace current largest even currO = num print("Largest odd number is ", currO)list_num = [1, 3, 5, 8, 6, 10]# creating an object of classobj = LargestOddAndEven()# calling method for largest even numberobj.largestEven(list_num)# calling method for largest odd numberobj.largestOdd(list_num) |
Output:
Largest even number is 10 Largest odd number is 5
The second approach, uses an optimised version of first approach, where in we compute both the largest values in one method itself. We still maintain two counters, but the for loop that iterates over the list runs only once.
Python3
class LargestOddAndEven: # find largest even number of the list def largestEvenandOdd(self, list): # counter for current largest even # number curr = -1 # counter for current largest odd # number currO = -1 for num in list: # converting number to integer # explicitly num = int(num) # even number is divisible by 2 and # if larger than current largest if(num % 2 == 0 and num > curr): # replace current largest even curr = num elif(num % 2 == 1 and num > currO): # replace current largest even currO = num print("Largest odd number is ", currO) print("Largest even number is ", curr)# input a list of numberslist_num = [123, 234, 236, 694, 809]# creating an object of classobj = LargestOddAndEven()# calling method for largest even and odd numberobj.largestEvenandOdd(list_num) |
Output:
Largest odd number is 809 Largest even number is 694
Method 3: Using list Comprehension and max function in python:
- Store even and odd numbers in separate lists using list comprehension.
- print max() of corresponding lists.
Below is the implementation of above approach:
Python3
# Python program for the above approachdef printmax(lis): # Using list comprehension storing # even and odd numbers as separate lists even = [x for x in lis if x % 2 == 0] odd = [x for x in lis if x % 2 == 1] # printing max numbers in corresponding lists print("Largest odd number is ", max(odd)) print("Largest even number is ", max(even))# Input a list of numberslis = [123, 234, 236, 694, 809]printmax(lis)# This code is contributed by vikkycirus |
Output:
Largest odd number is 809 Largest even number is 694
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