Python program to print odd numbers in a List
Given a list of numbers, write a Python program to print all odd numbers in given list.
Example:
Input: list1 = [2, 7, 5, 64, 14] Output: [7, 5] Input: list2 = [12, 14, 95, 3, 73] Output: [95, 3, 73]
 Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number.
# Python program to print odd Numbers in a List
# list of numbers
list1
=
[
10
,
21
,
4
,
45
,
66
,
93
]
# iterating each number in list
for
num
in
list1:
# checking condition
if
num
%
2
!
=
0
:
print
(num, end
=
" "
)
chevron_rightfilter_noneOutput:
21 45 93
 Using while loop :
# Python program to print odd Numbers in a List
# list of numbers
list1
=
[
10
,
21
,
4
,
45
,
66
,
93
]
i
=
0
# using while loop
while
(i <
len
(list1)):
# checking condition
if
list1[i]
%
2
!
=
0
:
print
(list1[i], end
=
" "
)
# increment i
i
+
=
1
chevron_rightfilter_noneOutput:
21 45 93
 Using list comprehension :
# Python program to print odd Numbers in a List
# list of numbers
list1
=
[
10
,
21
,
4
,
45
,
66
,
93
]
only_odd
=
[num
for
num
in
list1
if
num
%
2
=
=
1
]
print
(only_odd)
chevron_rightfilter_noneOutput:
21 45 93

Using lambda expressions :
# Python program to print odd numbers in a List
# list of numbers
list1
=
[
10
,
21
,
4
,
45
,
66
,
93
,
11
]
# we can also print odd no's using lambda exp.
odd_nos
=
list
(
filter
(
lambda
x: (x
%
2
!
=
0
), list1))
print
(
"Odd numbers in the list: "
, odd_nos)
chevron_rightfilter_noneOutput:
Odd numbers in the list: [21, 45, 93, 11]
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