Python Program to Compute Life Path Number
Last Updated :
22 Apr, 2023
Given a String of date of format YYYYMMDD, our task is to compute the life path number. Life Path Number is the number obtained by summation of individual digits of each element repeatedly till single digit, of datestring. Used in Numerology Predictions.
Examples:
Input : test_str = “19970314”
Output : 7
Explanation : 1 + 9 + 9 + 7 = 26 , 2 + 6 = 8 [ year ] ; 0 + 3 = 3 [ month ] ; 1 + 4 = 5 [ day ]. 5 + 3 + 8 = 16 ; 1 + 6 = 7.
Input : test_str = “19970104”
Output : 4
Explanation : 1 + 9 + 9 + 7 = 26 , 2 + 6 = 8 [ year ] ; 0 + 1 = 1 [ month ] ; 0 + 4 = 4 [ day ]. 4 + 1 + 8 = 13 ; 1 + 3 = 4.
Method 1: Using loop
The logic behind computing this is getting a summation of each digit and perform %10 at each step. This way result curlers to single digit if it goes to double-digit.
Python3
test_str = "19970314"
print ( "The original string is : " + str (test_str))
res = 0
for num in test_str:
res + = int (num)
if res > 9 :
res = res % 10 + res / / 10
print ( "Life Path Number : " + str (res))
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Output:
The original string is : 19970314
Life Path Number : 7
Time Complexity: O(n)
Space Complexity: O(n)
Method 2: Using recursion
Similar way as above, the difference being the recursive function is used for repeated modulation in case of digit count greater than 1.
Python3
test_str = "19970314"
print ( "The original string is : " + str (test_str))
def lpn(num): return num if num < 10 else lpn(num / / 10 + num % 10 )
res = lpn( int (test_str))
print ( "Life Path Number : " + str (res))
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Output:
The original string is : 19970314
Life Path Number : 7
Time Complexity: O(n)
Auxiliary Space: O(n)
Method 3: Using reduce()
This method uses reduce function from functools module to perform the computation in a single line code.
Python3
from functools import reduce
test_str = "19970314"
print ( "The original string is : " + str (test_str))
res = reduce ( lambda x, y : x + int (y), test_str, 0 )
while res > 9 :
res = reduce ( lambda x, y : x + int (y), str (res), 0 )
print ( "Life Path Number : " + str (res))
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Output
The original string is : 19970314
Life Path Number : 7
Time Complexity: O(n)
Auxiliary Space: O(1)
Method 4: Using mathematical formulas
Step-by-Step approach:
Initialize the input string test_str as “19970314”
Compute the sum of all the digits of the string by using the following formula:
sum = (int(test_str[0]) + int(test_str[1]) + int(test_str[2]) + int(test_str[3]) + int(test_str[4]) + int(test_str[5]) + int(test_str[6]) + int(test_str[7]))
Repeat step 2 until the sum obtained is less than or equal to 9.
Return the sum obtained as the Life Path Number.
Python3
test_str = "19970314"
print ( "The original string is : " + str (test_str))
while len (test_str) > 1 :
sum = 0
for digit in test_str:
sum + = int (digit)
test_str = str ( sum )
print ( "Life Path Number : " + str (test_str))
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Output
The original string is : 19970314
Life Path Number : 7
Time Complexity: O(n)
Auxiliary Space: O(1)
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