Python Program to check whether all elements in a string list are numeric

Given a list that contains only string elements the task here is to write a Python program to check if all of them are numeric or not. If all are numeric return True otherwise, return False.

Input : test_list = [“434”, “823”, “98”, “74”]

Output : True

Explanation : All Strings are digits.

Input : test_list = [“434”, “82e”, “98”, “74”]

Output : False

Explanation : e is not digit, hence verdict is False.

Method 1 : Using all(), isdigit() and generator expression

In this, we check for number from isdigit(). all() is used to check for all strings to be number, iteration for each string is done using generator expression.

Example:

Python3

# initializing list
test_list = ["434", "823", "98", "74"]

# printing original list
print("The original list is : " + str(test_list))

# checking all elements to be numeric using isdigit()
res = all(ele.isdigit() for ele in test_list)

# printing result
print("Are all strings digits ? : " + str(res))

Output:

The original list is : [‘434’, ‘823’, ’98’, ’74’]

Are all strings digits ? : True

Method 2 : Using  all(), isdigit() and map()

In this, we extend test logic to each string using map(), rather than generator expression. Rest all the functionalities are performed similar to above method.

Example:

Python3

# initializing list
test_list = ["434", "823", "98", "74"]

# printing original list
print("The original list is : " + str(test_list))

# checking all elements to be numeric using isdigit()
# map() to extend to each element
res = all(map(str.isdigit, test_list))

# printing result
print("Are all strings digits ? : " + str(res))

Output:

The original list is : [‘434’, ‘823’, ’98’, ’74’]

Are all strings digits ? : True