Given a list that contains only string elements the task here is to write a Python program to check if all of them are numeric or not. If all are numeric return True otherwise, return False.
Input : test_list = [“434”, “823”, “98”, “74”]
Output : True
Explanation : All Strings are digits.
Input : test_list = [“434”, “82e”, “98”, “74”]
Output : False
Explanation : e is not digit, hence verdict is False.
Method 1 : Using all(), isdigit() and generator expression
In this, we check for number from isdigit(). all() is used to check for all strings to be number, iteration for each string is done using generator expression.
Example:
Python3
# initializing listtest_list = ["434", "823", "98", "74"] # printing original listprint("The original list is : " + str(test_list)) # checking all elements to be numeric using isdigit()res = all(ele.isdigit() for ele in test_list) # printing resultprint("Are all strings digits ? : " + str(res)) |
Output:
The original list is : [‘434’, ‘823’, ’98’, ’74’]
Are all strings digits ? : True
Method 2 : Using all(), isdigit() and map()
In this, we extend test logic to each string using map(), rather than generator expression. Rest all the functionalities are performed similar to above method.
Example:
Python3
# initializing listtest_list = ["434", "823", "98", "74"] # printing original listprint("The original list is : " + str(test_list)) # checking all elements to be numeric using isdigit()# map() to extend to each elementres = all(map(str.isdigit, test_list)) # printing resultprint("Are all strings digits ? : " + str(res)) |
Output:
The original list is : [‘434’, ‘823’, ’98’, ’74’]
Are all strings digits ? : True
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