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Python Program to Find the Number Occurring Odd Number of Times
• Last Updated : 28 Oct, 2019

Given an array of positive integers. All numbers occur even number of times except one number which occurs odd number of times. Find the number in O(n) time & constant space.

Examples :

```Input : arr = {1, 2, 3, 2, 3, 1, 3}
Output : 3

Input : arr = {5, 7, 2, 7, 5, 2, 5}
Output : 5
```

## Python3

 `# Python program to find the element occurring``# odd number of times``     ` `# function to find the element occurring odd``# number of times``def` `getOddOccurrence(arr, arr_size):``     ` `    ``for` `i ``in` `range``(``0``, arr_size):``        ``count ``=` `0``        ``for` `j ``in` `range``(``0``, arr_size):``            ``if` `arr[i] ``=``=` `arr[j]:``                ``count``+``=` `1``             ` `        ``if` `(count ``%` `2` `!``=` `0``):``            ``return` `arr[i]``         ` `    ``return` `-``1``     ` `     ` `# driver code ``arr ``=` `[``2``, ``3``, ``5``, ``4``, ``5``, ``2``, ``4``, ``3``, ``5``, ``2``, ``4``, ``4``, ``2` `]``n ``=` `len``(arr)``print``(getOddOccurrence(arr, n))`` ` `# This code has been contributed by ``# Smitha Dinesh Semwal`
Output:
```5
```

A Better Solution is to use Hashing. Use array elements as key and their counts as value. Create an empty hash table. One by one traverse the given array elements and store counts. Time complexity of this solution is O(n). But it requires extra space for hashing.

Program :

## Python

 `     ` `# Python program to find the element occurring odd number of times`` ` `def` `getOddOccurrence(arr):`` ` `    ``# Initialize result``    ``res ``=` `0``     ` `    ``# Traverse the array``    ``for` `element ``in` `arr:``        ``# XOR with the result``        ``res ``=` `res ^ element`` ` `    ``return` `res`` ` `# Test array``arr ``=` `[ ``2``, ``3``, ``5``, ``4``, ``5``, ``2``, ``4``, ``3``, ``5``, ``2``, ``4``, ``4``, ``2``]`` ` `print` `"% d"` `%` `getOddOccurrence(arr)`
Output:
```5
```

Please refer complete article on Find the Number Occurring Odd Number of Times for more details!

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