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# Python | Multiply each element in a sublist by its index

• Last Updated : 29 May, 2019

Given a list of lists, the task is to multiply each element in a sublist by its index and return a summed list.

Given below are a few methods to solve the problem.

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Method #1: Using Naive Method

 `# Python3 code to demonstrate``# to multiply numbers with position``# and add them to return num`` ` `import` `numpy as np`` ` `# initialising list``ini_list ``=` `[[``3``, ``4``, ``7``], [ ``6``, ``7``, ``8``], [ ``10``, ``7``, ``5``], [ ``11``, ``12``, ``13``]]`` ` `# printing initial_list``print` `(``"initial_list "``, ini_list)`` ` `res ``=` `[]``# Using Naive Method``for` `sub_list ``in` `ini_list:``    ``sublistsum ``=` `0`` ` `    ``for` `i, value ``in` `enumerate``(sub_list):``        ``sublistsum ``=` `sublistsum ``+` `i ``*` `value`` ` `    ``res.append(sublistsum)`` ` `# printing result``print` `(``"result"``, res)`
Output:
```initial_list  [[3, 4, 7], [6, 7, 8], [10, 7, 5], [11, 12, 13]]
result [18, 23, 17, 38]
```

Method #2: Using List comprehension

 `# Python3 code to demonstrate``# to multiply numbers with position``# and add them to return num`` ` ` ` `# initialising list``ini_list ``=` `[[``3``, ``4``, ``7``], [ ``6``, ``7``, ``8``], [ ``10``, ``7``, ``5``], [ ``11``, ``12``, ``13``]]`` ` `# printing initial_list``print` `(``"initial_list "``, ini_list)`` ` `# Using list comprehension``res ``=` `[``sum``(i ``*` `j ``for` `i, j ``in` `enumerate``(sublist)) ``                         ``for` `sublist ``in` `ini_list]`` ` `# printing result``print` `(``"result"``, res)``            `
Output:
```initial_list  [[3, 4, 7], [6, 7, 8], [10, 7, 5], [11, 12, 13]]
result [18, 23, 17, 38]
```

Method #3: Using numpy

 `# Python3 code to demonstrate``# to multiply numbers with position``# and add them to return num`` ` `import` `numpy as np`` ` `# initialising list``ini_list ``=` `[[``3``, ``4``, ``7``], [ ``6``, ``7``, ``8``], [ ``10``, ``7``, ``5``], [ ``11``, ``12``, ``13``]]`` ` `# printing initial_list``print` `(``"initial_list "``, ini_list)`` ` `# Using numpy``res ``=` `[np.arange(``len``(sublist)).dot(sublist) ``for` `sublist ``in` `ini_list]`` ` `# printing result``print` `(``"result"``, res)``             ` `            `
Output:
```initial_list  [[3, 4, 7], [6, 7, 8], [10, 7, 5], [11, 12, 13]]
result [18, 23, 17, 38]
```

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