Skip to content
Related Articles

Related Articles

Improve Article
Save Article
Like Article

Python – K list Nested Dictionary Mesh

  • Last Updated : 02 Sep, 2020

Given 2 lists, create nested mesh with constant List.

Input : test_list1 = [4, 6], test_list2 = [2, 7], K = []
Output : {4: {2: [], 7: []}, 6: {2: [], 7: []}}
Explanation : Nested dictionary initialized with [].

 Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.  

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course. And to begin with your Machine Learning Journey, join the Machine Learning - Basic Level Course

Input : test_list1 = [4], test_list2 = [2], K = [1]
Output : {4: {2: [1]}}
Explanation : Nested dictionary initialized with [1].



Method : Using dictionary comprehension

In this, we use nested dictionary comprehension, inner one for list 2 elements to each element of list 1 as key and outer to assign keys from list 1.

Python3




# Python3 code to demonstrate working of 
# K list Nested Dictionary Mesh
# Using * operator
  
# initializing lists
test_list1 = [4, 6, 8, 7]
test_list2 = [2, 7, 9, 4]
  
# printing original lists
print("The original list 1 : " + str(test_list1))
print("The original list 2 : " + str(test_list2))
  
# initializing K 
K = [None]
  
# initializing K list mesh
res = {idx: {sub2: K for sub2 in test_list2} for idx in test_list1}
  
# printing result 
print("Created Mesh : " + str(res))
Output
The original list 1 : [4, 6, 8, 7]
The original list 2 : [2, 7, 9, 4]
Created Mesh : {4: {2: [None], 7: [None], 9: [None], 4: [None]}, 6: {2: [None], 7: [None], 9: [None], 4: [None]}, 8: {2: [None], 7: [None], 9: [None], 4: [None]}, 7: {2: [None], 7: [None], 9: [None], 4: [None]}}
My Personal Notes arrow_drop_up
Recommended Articles
Page :