Python – K list Nested Dictionary Mesh
Given 2 lists, create nested mesh with constant List.
Input : test_list1 = [4, 6], test_list2 = [2, 7], K = []
Output : {4: {2: [], 7: []}, 6: {2: [], 7: []}}
Explanation : Nested dictionary initialized with [].Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.
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Input : test_list1 = [4], test_list2 = [2], K = [1]
Output : {4: {2: [1]}}
Explanation : Nested dictionary initialized with [1].
Method : Using dictionary comprehension
In this, we use nested dictionary comprehension, inner one for list 2 elements to each element of list 1 as key and outer to assign keys from list 1.
Python3
# Python3 code to demonstrate working of # K list Nested Dictionary Mesh# Using * operator # initializing liststest_list1 = [4, 6, 8, 7]test_list2 = [2, 7, 9, 4] # printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2)) # initializing K K = [None] # initializing K list meshres = {idx: {sub2: K for sub2 in test_list2} for idx in test_list1} # printing result print("Created Mesh : " + str(res)) |
The original list 1 : [4, 6, 8, 7]
The original list 2 : [2, 7, 9, 4]
Created Mesh : {4: {2: [None], 7: [None], 9: [None], 4: [None]}, 6: {2: [None], 7: [None], 9: [None], 4: [None]}, 8: {2: [None], 7: [None], 9: [None], 4: [None]}, 7: {2: [None], 7: [None], 9: [None], 4: [None]}}
