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Python | Find sum of frequency of given elements in the list
• Last Updated : 08 Apr, 2019

Given two lists containing integers, the task is to find sum of frequency of element of first list in second list.

Example:

```Input: list1 = [1, 2, 3]
list2 = [2, 1, 2, 1, 3, 5, 2, 3]

Output: 7

Explanation:
No of time 1 occurring in list2 is :2
No of time 2 occurring in list2 is :3
No of time 3 occurring in list2 is :2
Sum = 2+3+2 = 7
```

Below are some ways to achieve the above tasks.

Method #1: Using `sum()`

 `# Python code to find sum of frequency of ``# element of first list in second list.`` ` `# List initialization``Input1 ``=` `[``1``, ``2``, ``3``]``Input2 ``=` `[``2``, ``1``, ``2``, ``1``, ``3``, ``5``, ``2``, ``3``]`` ` `# Using sum``Output ``=` `sum``(Input2.count(elem) ``for` `elem ``in` `Input1)`` ` `# Printing output``print``(``"Initial list are:"``, Input1, Input2)``print``(``"Frequency is:"``, Output)`
Output:

```Initial list are: [1, 2, 3] [2, 1, 2, 1, 3, 5, 2, 3]
Frequency is: 7
```

Method #2: Using `sum()` and `Counter()`

 `from` `collections ``import` `Counter`` ` `# List initialization``Input1 ``=` `[``1``, ``2``, ``3``]``Input2 ``=` `[``2``, ``1``, ``2``, ``1``, ``3``, ``5``, ``2``, ``3``]`` ` ` ` `temp ``=` `Counter(Input2)``Output ``=` `sum``(temp[x] ``for` `x ``in` `Input1)`` ` `# Printing output``print``(``"Initial list are:"``, Input1, Input2)``print``(``"Frequency is:"``, Output)`
Output:
```Initial list are: [1, 2, 3] [2, 1, 2, 1, 3, 5, 2, 3]
Frequency is: 7
```

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