Python | Find dictionary matching value in list

• Last Updated : 02 Aug, 2019

The problem of getting only the suitable dictionary that has a particular value of the corresponding key is quite common when one starts working with dictionary. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is the brute force method by which this task can be performed. For this, we just use naive check and compare and return the result once we find the suitable match and break for rest of dictionaries.

 `# Python3 code to demonstrate working of``# Find dictionary matching value in list``# Using loop`` ` `# Initialize list``test_list ``=` `[{``'gfg'` `: ``2``, ``'is'` `: ``4``, ``'best'` `: ``6``}, ``             ``{``'it'` `: ``5``, ``'is'` `: ``7``, ``'best'` `: ``8``},``             ``{``'CS'` `: ``10``}]`` ` `# Printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# Using loop``# Find dictionary matching value in list``res ``=` `None``for` `sub ``in` `test_list:``    ``if` `sub[``'is'``] ``=``=` `7``:``        ``res ``=` `sub``        ``break`` ` `# printing result ``print``(``"The filtered dictionary value is : "` `+` `str``(res))`

Output :

```The original list is : [{'is': 4, 'gfg': 2, 'best': 6}, {'is': 7, 'best': 8, 'it': 5}, {'CS': 10}]
The filtered dictionary value is : {'is': 7, 'best': 8, 'it': 5}
```

Method #2 : Using `next()` + dictionary comprehension
The combination of these methods can also be used to perform this task. This difference is that it’s a one liner and more efficient as next function uses iterator as internal implementation which are quicker than generic methods.

 `# Python3 code to demonstrate working of``# Find dictionary matching value in list``# Using next() + dictionary comprehension`` ` `# Initialize list``test_list ``=` `[{``'gfg'` `: ``2``, ``'is'` `: ``4``, ``'best'` `: ``6``}, ``             ``{``'it'` `: ``5``, ``'is'` `: ``7``, ``'best'` `: ``8``},``             ``{``'CS'` `: ``10``}]`` ` `# Printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# Using next() + dictionary comprehension``# Find dictionary matching value in list``res ``=` `next``((sub ``for` `sub ``in` `test_list ``if` `sub[``'is'``] ``=``=` `7``), ``None``)`` ` `# printing result ``print``(``"The filtered dictionary value is : "` `+` `str``(res))`

Output :

```The original list is : [{'is': 4, 'gfg': 2, 'best': 6}, {'is': 7, 'best': 8, 'it': 5}, {'CS': 10}]
The filtered dictionary value is : {'is': 7, 'best': 8, 'it': 5}
```

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