Python | Find dictionary matching value in list

The problem of getting only the suitable dictionary that has a particular value of the corresponding key is quite common when one starts working with dictionary. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is the brute force method by which this task can be performed. For this, we just use naive check and compare and return the result once we find the suitable match and break for rest of dictionaries.

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# Python3 code to demonstrate working of
# Find dictionary matching value in list
# Using loop
  
# Initialize list
test_list = [{'gfg' : 2, 'is' : 4, 'best' : 6}, 
             {'it' : 5, 'is' : 7, 'best' : 8},
             {'CS' : 10}]
  
# Printing original list
print("The original list is : " + str(test_list))
  
# Using loop
# Find dictionary matching value in list
res = None
for sub in test_list:
    if sub['is'] == 7:
        res = sub
        break
  
# printing result 
print("The filtered dictionary value is : " + str(res))

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Output :

The original list is : [{'is': 4, 'gfg': 2, 'best': 6}, {'is': 7, 'best': 8, 'it': 5}, {'CS': 10}]
The filtered dictionary value is : {'is': 7, 'best': 8, 'it': 5}

 

Method #2 : Using next() + dictionary comprehension
The combination of these methods can also be used to perform this task. This difference is that it’s a one liner and more efficient as next function uses iterator as internal implementation which are quicker than generic methods.

filter_none

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close

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code

# Python3 code to demonstrate working of
# Find dictionary matching value in list
# Using next() + dictionary comprehension
  
# Initialize list
test_list = [{'gfg' : 2, 'is' : 4, 'best' : 6}, 
             {'it' : 5, 'is' : 7, 'best' : 8},
             {'CS' : 10}]
  
# Printing original list
print("The original list is : " + str(test_list))
  
# Using next() + dictionary comprehension
# Find dictionary matching value in list
res = next((sub for sub in test_list if sub['is'] == 7), None)
  
# printing result 
print("The filtered dictionary value is : " + str(res))

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Output :

The original list is : [{'is': 4, 'gfg': 2, 'best': 6}, {'is': 7, 'best': 8, 'it': 5}, {'CS': 10}]
The filtered dictionary value is : {'is': 7, 'best': 8, 'it': 5}


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