Skip to content
Related Articles

Related Articles

Improve Article

Python Dictionary to find mirror characters in a string

  • Difficulty Level : Easy
  • Last Updated : 26 May, 2021
Geek Week

Given a string and a number N, we need to mirror the characters from the N-th position up to the length of the string in alphabetical order. In mirror operation, we change ‘a’ to ‘z’, ‘b’ to ‘y’, and so on.

Input : N = 3
Output : paizwlc
We mirror characters from position 3 to end.

Input : N = 6
Output : pneumlmrz


We have an existing solution for this problem please refer to Mirror characters of a string link. We can solve this problem in Python using Dictionary Data Structure. The mirror value of ‘a’ is ‘z’,’b’ is ‘y’, etc, so we create a dictionary data structure and one-to-one map reverse sequence of alphabets onto the original sequence of alphabets. Now traverse characters from length k in given string and change characters into their mirror value using a dictionary.


# function to mirror characters of a string
def mirrorChars(input,k):
    # create dictionary
    original = 'abcdefghijklmnopqrstuvwxyz'
    reverse = 'zyxwvutsrqponmlkjihgfedcba'
    dictChars = dict(zip(original,reverse))
    # separate out string after length k to change
    # characters in mirror
    prefix = input[0:k-1]
    suffix = input[k-1:]
    mirror = ''
    # change into mirror
    for i in range(0,len(suffix)):
         mirror = mirror + dictChars[suffix[i]]
    # concat prefix and mirrored part
    print (prefix+mirror)
# Driver program
if __name__ == "__main__":
    input = 'paradox'
    k = 3




 Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.  

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course. And to begin with your Machine Learning Journey, join the Machine Learning – Basic Level Course

My Personal Notes arrow_drop_up
Recommended Articles
Page :