Open In App
Related Articles

Python Dictionary to find mirror characters in a string

Improve Article
Save Article
Like Article

Given a string and a number N, we need to mirror the characters from the N-th position up to the length of the string in alphabetical order. In mirror operation, we change ‘a’ to ‘z’, ‘b’ to ‘y’, and so on.


Input : N = 3
Output : paizwlc
We mirror characters from position 3 to end.

Input : N = 6
Output : pneumlmrz

We have an existing solution for this problem please refer to Mirror characters of a string link. We can solve this problem in Python using Dictionary Data Structure. The mirror value of ‘a’ is ‘z’,’b’ is ‘y’, etc, so we create a dictionary data structure and one-to-one map reverse sequence of alphabets onto the original sequence of alphabets. Now traverse characters from length k in given string and change characters into their mirror value using a dictionary.



# function to mirror characters of a string
def mirrorChars(input,k):
    # create dictionary
    original = 'abcdefghijklmnopqrstuvwxyz'
    reverse = 'zyxwvutsrqponmlkjihgfedcba'
    dictChars = dict(zip(original,reverse))
    # separate out string after length k to change
    # characters in mirror
    prefix = input[0:k-1]
    suffix = input[k-1:]
    mirror = ''
    # change into mirror
    for i in range(0,len(suffix)):
         mirror = mirror + dictChars[suffix[i]]
    # concat prefix and mirrored part
    print (prefix+mirror)
# Driver program
if __name__ == "__main__":
    input = 'paradox'
    k = 3



Time complexity: O(n)
Auxiliary Space: O(n)

Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Last Updated : 28 Jul, 2022
Like Article
Save Article
Similar Reads
Related Tutorials