Given a Binary tree, the problem is to find mirror of a given node. The mirror of a node is a node which exist at the mirror position of node in opposite subtree at the root.
In above tree- Node 2 and 3 are mirror nodes Node 4 and 6 are mirror nodes.
We can have a recursive solution for finding mirror nodes. The algorithm is following –
1) Start from the root of the tree and recur nodes from both subtree simultaneously using two pointers for left and right nodes. 2) First recur all the external nodes and store returned value in mirror variable. 3) If current node value is equal to target node, return the value of opposite pointer else repeat step 2. 4) If no external node is left and mirror is none, recur internal nodes.
Mirror of node 4 is node 6
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