Python | Check if a given string is binary string or not
Given a string str. The task is to check whether it is a binary string or not.
Examples:
Input: str = "01010101010" Output: Yes Input: str = "geeks101" Output: No
Approach 1: Using Set
- Insert the given string in a set
- Check if the set characters consist of 1 and/or 0 only.
# Python program to check # if a string is binary or not # function for checking the # string is accepted or not def check(string) : # set function convert string # into set of characters . p = set(string) # declare set of '0', '1' . s = {'0', '1'} # check set p is same as set s # or set p contains only '0' # or set p contains only '1' # or not, if any one condition # is true then string is accepted # otherwise not . if s == p or p == {'0'} or p == {'1'}: print("Yes") else : print("No") # driver code if __name__ == "__main__" : string = "101010000111" # function calling check(string) |
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Output:
Yes
Approach 2: Simple Iteration
- Iterate for every character and check if the character is 0 or 1.
- If it is not then set a counter and break.
- After iteration check whether the counter is set or not.
# Python program to check # if a string is binary or not # function for checking the # string is accepted or not def check2(string) : # initialize the variable t # with '01' string t = '01' # initialize the variable count # with 0 value count = 0 # looping through each character # of the string . for char in string : # check the character is present in # string t or not. # if this condition is true # assign 1 to the count variable # and break out of the for loop # otherwise pass if char not in t : count = 1 break else : pass # after coming out of the loop # check value of count is non-zero or not # if the value is non-zero the en condition is true # and string is not accepted # otherwise string is accepted if count : print("No") else : print("Yes") # driver code if __name__ == "__main__" : string = "001021010001010" # function calling check2(string) |
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Output:
No
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