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Python – Assign keys with Maximum element index
  • Last Updated : 24 Jan, 2021

Given Dictionary with value lists, the task is to write a Python program to assign each key with an index of the maximum value in the value list.

Examples:

Input : test_dict = {“gfg” : [5, 3, 6, 3], “is” : [1, 7, 5, 3], “best” : [9, 1, 3, 5]}

Output : {‘gfg’: 2, ‘is’: 1, ‘best’: 0}

Explanation : Max element in “gfg”‘s value is 6 at 2nd index, hence assigned 2.



Input : test_dict = {“gfg” : [9, 3, 6, 3], “is” : [1, 7, 5, 3], “best” : [9, 1, 3, 5]}

Output : {‘gfg’: 0, ‘is’: 1, ‘best’: 0}

Explanation : Max element in “gfg”‘s value is 9 at 0th index, hence assigned 0.

Method #1 : Using max() + loop + index()

In this, we get the index of the maximum element from the value list using max() and index(). Loop is used for the task of iteration of keys in the dictionary.

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# Python3 code to demonstrate working of
# Assign keys with Maximum element index
# Using max() + index() + loop
  
# initializing dictionary
test_dict = {"gfg": [5, 3, 6, 3], "is": [1, 7, 5, 3], "best": [9, 1, 3, 5]}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
res = dict()
for key in test_dict:
  
    # using index() to get required value
    res[key] = test_dict[key].index(max(test_dict[key]))
  
# printing result
print("The maximum index assigned dictionary : " + str(res))

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Output:

The original dictionary is : {‘gfg’: [5, 3, 6, 3], ‘is’: [1, 7, 5, 3], ‘best’: [9, 1, 3, 5]}

The maximum index assigned dictionary : {‘gfg’: 2, ‘is’: 1, ‘best’: 0}



Method #2 : Using dictionary comprehension + max() + index()

In this, we perform task of getting result using dictionary comprehension shorthand variation of above method.

Python3

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# Python3 code to demonstrate working of
# Assign keys with Maximum element index
# Using dictionary comprehension + max() + index()
  
# initializing dictionary
test_dict = {"gfg": [5, 3, 6, 3], "is": [1, 7, 5, 3], "best": [9, 1, 3, 5]}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# using dictionary comprehension as one liner alternative
res = {key: test_dict[key].index(max(test_dict[key])) for key in test_dict}
  
# printing result
print("The maximum index assigned dictionary : " + str(res))

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Output:

The original dictionary is : {‘gfg’: [5, 3, 6, 3], ‘is’: [1, 7, 5, 3], ‘best’: [9, 1, 3, 5]}

The maximum index assigned dictionary : {‘gfg’: 2, ‘is’: 1, ‘best’: 0}

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