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PyQt5 QCalendarWidget – Checking if it is active window or not

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In this article, we will see how we can check if the QCalendarWidget is an active window. An active window is a visible top-level window that has the keyboard input focus. Making it an active window will set the top-level widget containing this calendar to be the active window. We can make it an active window with the help of activateWindow method.
Note: This method should be called outside the main window class else it will always return false

In order to do this we will use isActivateWindow method with the QCalendarWidget object.
Syntax : calendar.isActivateWindow()
Argument : It takes no argument
Action Performed : It return bool 

Below is the implementation 


# importing libraries
from PyQt5.QtWidgets import *
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys
class Window(QMainWindow):
    def __init__(self):
        # setting title
        self.setWindowTitle("Python ")
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
        # calling method
        # showing all the widgets
    # method for components
    def UiComponents(self):
        # creating a QCalendarWidget object
        self.calendar = QCalendarWidget(self)
        # setting geometry to the calendar
        self.calendar.setGeometry(10, 10, 400, 250)
        # setting name
        self.calendar.setAccessibleName("Geek Calendar")
        # making it an active window
        # creating a label
        label = QLabel(self)
        # setting geometry to the label
        label.setGeometry(100, 280, 250, 60)
        # making label multi line
        # checking active window
        value = self.calendar.isActiveWindow()
        # setting text to the label
        label.setText("Active Window(Checking inside the class) " + str(value))
# create pyqt5 app
App = QApplication(sys.argv)
# create the instance of our Window
window = Window()
# checking if active window
# outside the class
check = window.calendar.isActiveWindow()
print("Active window : " + str(check))
# start the app


Output : 

Active window : True



Last Updated : 08 Jul, 2021
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