# Program to find the Nth term of the series 0, 3/1, 8/3, 15/5……..

Given a number **N**, the task is to find the **Nth** term of the following series.

0, 3/1, 8/3, 15/5……

**Examples:**

Input:n=4Output:15/5Input:n=3Output:8/3

**Approach:** By clearly examining the series we can find the **Tn** term for the series and with the help of tn we can find the desired result.

Tn=0 + 3/1 +8/3 +15/5…….

We can see that here odd terms are negative and even terms are positiveTn=((n^{2}-1)/(2*n-3))

Below is the implementation of the above approach.

## CPP

`// C++ implementation of the approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to return the nth term of the given series` `void` `Nthterm(` `int` `n)` `{` ` ` `// nth term` ` ` `int` `numerator = ` `pow` `(n, 2) - 1;` ` ` `int` `denomenator = 2 * n - 3;` ` ` `cout << numerator << ` `"/"` `<< denomenator;` `}` `// Driver code` `int` `main()` `{` ` ` `int` `n = 3;` ` ` `Nthterm(n);` ` ` `return` `0;` `}` |

## Python

`# Python3 implementation of the approach ` ` ` `# Function to return the nth term of the given series ` `def` `Nthterm(n): ` ` ` ` ` `# nth term ` ` ` `numerator ` `=` `n` `*` `*` `2` `-` `1` ` ` `denomenator ` `=` `2` `*` `n` `-` `3` ` ` ` ` `print` `(numerator, ` `"/"` `, denomenator)` ` ` ` ` `# Driver code ` `n ` `=` `3` `Nthterm(n)` |

## Java

`// Java implementation of the approach` `import` `java.util.*;` `import` `java.lang.*;` `import` `java.io.*;` `public` `class` `GFG {` ` ` `// Function to return the nth term of the given series` ` ` `static` `void` `NthTerm(` `int` `n)` ` ` `{` ` ` `int` `numerator` ` ` `= ((` `int` `)Math.pow(n, ` `2` `)) - ` `1` `;` ` ` `int` `denomeanator = ` `2` `* n - ` `3` `;` ` ` `System.out.println(numerator + ` `"/"` `+ denomeanator);` ` ` `}` ` ` `// Driver code` ` ` `public` `static` `void` `main(String[] args)` ` ` `{` ` ` `int` `n = ` `3` `;` ` ` `NthTerm(n);` ` ` `}` `}` |

## C#

`// C# implementation of the approach` `using` `System;` `public` `class` `GFG {` ` ` `// Function to return the nth term of the given series` ` ` `static` `void` `NthTerm(` `int` `n)` ` ` `{` ` ` `int` `numerator` ` ` `= ((` `int` `)Math.Pow(n, 2)) - 1;` ` ` `int` `denomeanator = 2 * n - 3;` ` ` `Console.WriteLine(numerator + ` `"/"` `+ denomeanator);` ` ` `}` ` ` `// Driver code` ` ` `public` `static` `void` `Main()` ` ` `{` ` ` `int` `n = 3;` ` ` `NthTerm(n);` ` ` `}` `}` |

## PHP

`<?php` `// PHP implementation of the approach` `// Function to return the nth term of the given series` `function` `Nthterm(` `$n` `)` `{` ` ` `$numerator` `= (pow(` `$n` `, 2)) -1;` ` ` `$denomenator` `=2*` `$n` `-3;` ` ` `echo` `$numerator` `, ` `"/"` `, ` `$denomenator` `;` ` ` `return` `$Tn` `;` ` ` `}` ` ` `// Driver code` `$n` `= 3;` `Nthterm(` `$n` `);` `?> ` |

## Javascript

`<script>` `// javascript implementation of the approach` `// Function to return the nth term of the given series` `function` `Nthterm( n)` `{` ` ` `// nth term` ` ` `let numerator = Math.pow(n, 2) - 1;` ` ` `let denomenator = 2 * n - 3;` ` ` `document.write( numerator + ` `"/"` `+ denomenator);` `}` `// Driver code` `let n = 3;` ` ` `Nthterm(n);` `// This code contributed by gauravrajput1` `</script>` |

**Output:**

8/3

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