Given a number **N**, the task is to find the **Nth** term of the following series.

0, 3/1, 8/3, 15/5……

**Examples:**

Input:n=4Output:15/5Input:n=3Output:8/3

**Approach:** By clearly examining the series we can find the **Tn** term for the series and with the help of tn we can find the desired result.

Tn=0 + 3/1 +8/3 +15/5…….

We can see that here odd terms are negative and even terms are positive

Tn=((n^{2}-1)/(2*n-3))

Below is the implementation of the above approach.

## CPP

`// C++ implementation of the approach ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to return the nth term of the given series ` `void` `Nthterm(` `int` `n) ` `{ ` ` ` ` ` `// nth term ` ` ` `int` `numerator = ` `pow` `(n, 2) - 1; ` ` ` `int` `denomenator = 2 * n - 3; ` ` ` `cout << numerator << ` `"/"` `<< denomenator; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `int` `n = 3; ` ` ` ` ` `Nthterm(n); ` ` ` ` ` `return` `0; ` `} ` |

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## Python

`# Python3 implementation of the approach ` ` ` `# Function to return the nth term of the given series ` `def` `Nthterm(n): ` ` ` ` ` `# nth term ` ` ` `numerator ` `=` `n` `*` `*` `2` `-` `1` ` ` `denomenator ` `=` `2` `*` `n` `-` `3` ` ` ` ` `print` `(numerator, ` `"/"` `, denomenator) ` ` ` ` ` `# Driver code ` `n ` `=` `3` `Nthterm(n) ` |

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## Java

`// Java implementation of the approach ` `import` `java.util.*; ` `import` `java.lang.*; ` `import` `java.io.*; ` ` ` `public` `class` `GFG { ` ` ` ` ` `// Function to return the nth term of the given series ` ` ` `static` `void` `NthTerm(` `int` `n) ` ` ` `{ ` ` ` `int` `numerator ` ` ` `= ((` `int` `)Math.pow(n, ` `2` `)) - ` `1` `; ` ` ` `int` `denomeanator = ` `2` `* n - ` `3` `; ` ` ` `System.out.println(numerator + ` `"/"` `+ denomeanator); ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `main(String[] args) ` ` ` `{ ` ` ` `int` `n = ` `3` `; ` ` ` `NthTerm(n); ` ` ` `} ` `} ` |

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## C#

`// C# implementation of the approach ` `using` `System; ` `public` `class` `GFG { ` ` ` ` ` `// Function to return the nth term of the given series ` ` ` `static` `void` `NthTerm(` `int` `n) ` ` ` `{ ` ` ` ` ` `int` `numerator ` ` ` `= ((` `int` `)Math.Pow(n, 2)) - 1; ` ` ` `int` `denomeanator = 2 * n - 3; ` ` ` `Console.WriteLine(numerator + ` `"/"` `+ denomeanator); ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` `int` `n = 3; ` ` ` `NthTerm(n); ` ` ` `} ` `} ` |

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## PHP

`<?php ` `// PHP implementation of the approach ` ` ` `// Function to return the nth term of the given series ` `function` `Nthterm(` `$n` `) ` `{ ` ` ` ` ` `$numerator` `= (pow(` `$n` `, 2)) -1; ` ` ` `$denomenator` `=2*` `$n` `-3; ` ` ` ` ` `echo` `$numerator` `, ` `"/"` `, ` `$denomenator` `; ` ` ` `return` `$Tn` `; ` ` ` `} ` ` ` `// Driver code ` `$n` `= 3; ` `Nthterm(` `$n` `); ` `?> ` |

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**Output:**

8/3

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