Given two integers **A** and **B**, representing the length of the semi-major and semi-minor axis of a Hyperbola of the equation **(X ^{2 }/ A^{2}) – (Y^{2 }/ B^{2}) = 1**, the task is to calculate the eccentricity of the given hyperbola.

**Examples:**

Input:A = 3, B = 2Output:1.20185Explanation:

The eccentricity of the given hyperbola is 1.20185.

Input:A = 6, B = 3Output:1.11803

**Approach:** The given problem can be solved by using the formula to find the eccentricity of an ellipse.

- The length of the semi-major axis is
**A**. - The length of the semi-minor axis is
**B**. - Therefore, the eccentricity of the ellipse is given by where A > B

Therefore, the idea is to print the value of as the eccentricity of the ellipse.

Below is the implementation of the above approach:

## C++

`// C++ program for the above approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to find the eccentricity` `// of a hyperbola` `double` `eccHyperbola(` `double` `A, ` `double` `B)` `{` ` ` `// Stores the squared ratio` ` ` `// of major axis to minor axis` ` ` `double` `r = (` `double` `)B * B / A * A;` ` ` `// Increment r by 1` ` ` `r += 1;` ` ` `// Return the square root of r` ` ` `return` `sqrt` `(r);` `}` `// Driver Code` `int` `main()` `{` ` ` `double` `A = 3.0, B = 2.0;` ` ` `cout << eccHyperbola(A, B);` ` ` `return` `0;` `}` |

## Java

`// Java program for the above approach` `import` `java.util.*;` `class` `GFG{` `// Function to find the eccentricity` `// of a hyperbola` `static` `double` `eccHyperbola(` `double` `A, ` `double` `B)` `{` ` ` ` ` `// Stores the squared ratio` ` ` `// of major axis to minor axis` ` ` `double` `r = (` `double` `)B * B / A * A;` ` ` `// Increment r by 1` ` ` `r += ` `1` `;` ` ` `// Return the square root of r` ` ` `return` `Math.sqrt(r);` `}` `// Driver Code` `public` `static` `void` `main(String[] args)` `{` ` ` `double` `A = ` `3.0` `, B = ` `2.0` `;` ` ` ` ` `System.out.print(eccHyperbola(A, B));` `}` `}` `// This code is contributed by Amit Katiyar` |

## Python3

`# Python3 program for the above approach` `import` `math` `# Function to find the eccentricity` `# of a hyperbola` `def` `eccHyperbola(A, B):` ` ` `# Stores the squared ratio` ` ` `# of major axis to minor axis` ` ` `r ` `=` `B ` `*` `B ` `/` `A ` `*` `A` ` ` `# Increment r by 1` ` ` `r ` `+` `=` `1` ` ` `# Return the square root of r` ` ` `return` `math.sqrt(r)` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `A ` `=` `3.0` ` ` `B ` `=` `2.0` ` ` `print` `(eccHyperbola(A, B))` ` ` `# This code is contributed by ukasp` |

## C#

`// C# program for the above approach` `using` `System;` `class` `GFG{` `// Function to find the eccentricity` `// of a hyperbola` `static` `double` `eccHyperbola(` `double` `A, ` `double` `B)` `{` ` ` ` ` `// Stores the squared ratio` ` ` `// of major axis to minor axis` ` ` `double` `r = (` `double` `)B * B / A * A;` ` ` `// Increment r by 1` ` ` `r += 1;` ` ` `// Return the square root of r` ` ` `return` `Math.Sqrt(r);` `}` `// Driver Code` `public` `static` `void` `Main(String[] args)` `{` ` ` `double` `A = 3.0, B = 2.0;` ` ` ` ` `Console.Write(eccHyperbola(A, B));` `}` `}` `// This code is contributed by Princi Singh` |

## Javascript

`<script>` `// Javascript program for the above approach` `// Function to find the eccentricity` `// of a hyperbola` `function` `eccHyperbola(A, B)` `{` ` ` ` ` `// Stores the squared ratio` ` ` `// of major axis to minor axis` ` ` `let r = B * B / A * A;` ` ` `// Increment r by 1` ` ` `r += 1;` ` ` `// Return the square root of r` ` ` `return` `Math.sqrt(r);` `}` `// Driver Code` `let A = 3.0;` `let B = 2.0;` `document.write(eccHyperbola(A, B));` `// This code is contributed by mohit kumar` `</script>` |

**Output:**

2.23607

**Time Complexity:** O(1)**Auxiliary Space:** O(1)

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