# Program to convert Number in characters

• Difficulty Level : Basic
• Last Updated : 08 Dec, 2021

Given an Integer N. The task is to convert the number in characters.

Examples:

Input: N = 74254
Output: Seven four two five four

Input: N = 23
Output: Two three

An efficient approach:

1. Reverse the number.
2. Iterate through the reversed number from right to left.
3. Extract the last digit by using modulus, then use switch case to get the corresponding word.
4. While iterating divide the number by 10.

## C++

 `// C++ program to convert number in characters``#include``using` `namespace` `std;``void` `NumbertoCharacter(``int` `n)``{``    ``int` `rev = 0, r = 0;` `    ``// To calculate the reverse of the number``    ``while` `(n > 0) {` `        ``// The remainder will give the last digit of the number``        ``r = n % 10;``        ``rev = rev * 10 + r;``        ``n = n / 10;``    ``}` `    ``while` `(rev > 0) {``        ``// Extract the first digit of the reversed number``        ``r = rev % 10;` `        ``// Match it with switch case``        ``switch` `(r) {``        ``case` `1:``            ``cout << ``"one "``;``            ``break``;``        ``case` `2:``            ``cout << ``"two "``;``            ``break``;``        ``case` `3:``            ``cout << ``"three "``;``            ``break``;``        ``case` `4:``            ``cout << ``"four "``;``            ``break``;``        ``case` `5:``            ``cout << ``"five "``;``            ``break``;``        ``case` `6:``            ``cout << ``"six "``;``            ``break``;``        ``case` `7:``            ``cout << ``"seven "``;``            ``break``;``        ``case` `8:``            ``cout << ``"eight "``;``            ``break``;``        ``case` `9:``            ``cout << ``"nine "``;``            ``break``;``        ``case` `0:``            ``cout << ``"zero "``;``            ``break``;``        ``default``:``            ``cout << ``"inValid "``;``            ``break``;``        ``}` `        ``// Divide the number by 10 to get the next number``        ``rev = rev / 10;``    ``}``}``// Driver code``#include ``int` `main()``{``    ``int` `n = 12345;``    ``NumbertoCharacter(n);``    ``return` `0;``}`

## Java

 `// Java program to convert number in characters``class` `GFG{``    ` `static` `void` `NumbertoCharacter(``int` `n)``{``    ``int` `rev = ``0``, r = ``0``;` `    ``// To calculate the reverse of the number``    ``while` `(n > ``0``)``    ``{` `        ``// The remainder will give``        ``// the last digit of the number``        ``r = n % ``10``;``        ``rev = rev * ``10` `+ r;``        ``n = n / ``10``;``    ``}``    ` `    ``while` `(rev > ``0``)``    ``{` `        ``// Extract the first digit``        ``// of the reversed number``        ``r = rev % ``10``;` `        ``// Match it with switch case``        ``switch` `(r)``        ``{``        ``case` `1``:``            ``System.out.print(``"one "``);``            ``break``;``        ``case` `2``:``            ``System.out.print(``"two "``);``            ``break``;``        ``case` `3``:``            ``System.out.print(``"three "``);``            ``break``;``        ``case` `4``:``            ``System.out.print(``"four "``);``            ``break``;``        ``case` `5``:``            ``System.out.print(``"five "``);``            ``break``;``        ``case` `6``:``            ``System.out.print(``"six "``);``            ``break``;``        ``case` `7``:``            ``System.out.print(``"seven "``);``            ``break``;``        ``case` `8``:``            ``System.out.print(``"eight "``);``            ``break``;``        ``case` `9``:``            ``System.out.print(``"nine "``);``            ``break``;``        ``case` `0``:``            ``System.out.print(``"zero "``);``            ``break``;``        ``default``:``            ``System.out.print(``"InValid "``);``            ``break``;``        ``}` `        ``// Divide the number by 10``        ``// to get the next number``        ``rev = rev / ``10``;``    ``}``}` `// Driver code``public` `static` `void` `main(String[] args)``{``    ``int` `n = ``12345``;``    ``NumbertoCharacter(n);``}``}` `// This code is contributed by Amit Katiyar`

## Python3

 `# Python3 program to convert``# number in characters``def` `NumbertoCharacter(n):``    ``rev ``=` `0``; r ``=` `0``;` `    ``# To calculate the``    ``# reverse of the number``    ``while` `(n > ``0``):` `        ``# The remainder will give``        ``# the last digit of the number``        ``r ``=` `n ``%` `10``;``        ``rev ``=` `rev ``*` `10` `+` `r;``        ``n ``=` `n ``/``/` `10``;   ` `    ``while` `(rev > ``0``):` `        ``# Extract the first digit``        ``# of the reversed number``        ``r ``=` `rev ``%` `10``;` `        ``# Match it with switch case``        ``switcher ``=` `{``                ``0` `: ``"zero "``,``                ``1` `: ``"one "``,``                ``2` `: ``"two "``,``                ``3` `: ``"three "``,``                ``4` `: ``"four "``,``                ``5` `: ``"five "``,``                ``6` `: ``"six "``,``                ``7` `: ``"seven "``,``                ``8` `: ``"eight "``,``                ``9` `: ``"nine "``        ``}``        ``print``( switcher.get(r, ``"InValid"``),``               ``end ``=` `" "``) ;       ` `        ``# Divide the number by 10``        ``# to get the next number``        ``rev ``=` `rev ``/``/` `10``;` `# Driver code``if` `__name__ ``=``=` `'__main__'``:``    ``n ``=` `12345``;``    ``NumbertoCharacter(n);` `# This code is contributed by gauravrajput1`

## C#

 `// C# program to convert number in characters``using` `System;` `class` `GFG{``    ` `static` `void` `NumbertoCharacter(``int` `n)``{``    ``int` `rev = 0, r = 0;` `    ``// To calculate the reverse``    ``// of the number``    ``while` `(n > 0)``    ``{``        ` `        ``// The remainder will give``        ``// the last digit of the number``        ``r = n % 10;``        ``rev = rev * 10 + r;``        ``n = n / 10;``    ``}``    ` `    ``while` `(rev > 0)``    ``{` `        ``// Extract the first digit``        ``// of the reversed number``        ``r = rev % 10;` `        ``// Match it with switch case``        ``switch` `(r)``        ``{``            ``case` `1:``                ``Console.Write(``"one "``);``                ``break``;``            ``case` `2:``                ``Console.Write(``"two "``);``                ``break``;``            ``case` `3:``                ``Console.Write(``"three "``);``                ``break``;``            ``case` `4:``                ``Console.Write(``"four "``);``                ``break``;``            ``case` `5:``                ``Console.Write(``"five "``);``                ``break``;``            ``case` `6:``                ``Console.Write(``"six "``);``                ``break``;``            ``case` `7:``                ``Console.Write(``"seven "``);``                ``break``;``            ``case` `8:``                ``Console.Write(``"eight "``);``                ``break``;``            ``case` `9:``                ``Console.Write(``"nine "``);``                ``break``;``            ``case` `0:``                ``Console.Write(``"zero "``);``                ``break``;``            ``default``:``                ``Console.Write(``"inValid "``);``                ``break``;``        ``}` `        ``// Divide the number by 10``        ``// to get the next number``        ``rev = rev / 10;``    ``}``}` `// Driver code``public` `static` `void` `Main(String[] args)``{``    ``int` `n = 12345;``    ` `    ``NumbertoCharacter(n);``}``}` `// This code is contributed by sapnasingh4991`

## Javascript

 ``

Output:

`one two three four five`

Time complexity: O(k)
k is the length of the number.
Space complexity: O(1)

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