Program to convert Hexa-Decimal Number to its equivalent BCD

Given a HexaDecimal Number N, the task is to convert the number to its equivalent Binary Coded Decimal.

Examples:

Input: 11F
Output: 0001 0001 1111
Explanation:
Binary of 1 – 0001
Binary of F – 1111
Thus, Equivalent BCD is 0001 0001 1111

Input: A D
Output: 1010 1101
Explanation:
Binary of A – 1010
Binary of D – 1101
Thus, Equivalent BCD is 1010 1101

Approach: The idea is to iterate over each digit of the given Hexa-Decimal number and find the four digit Binary Equivalent of that digit. Finally, print all the converted digits one by one.

Below is the implementation of the above approach:

C++

// C++ implementation  to convert the given 
// HexaDecimal number to its equivalent BCD. 
  
#include <bits/stdc++.h> 
using namespace std; 
  
// Function to convert 
// HexaDecimal to its BCD 
void HexaDecimaltoBCD(string s) 
{ 
    int len = s.length(), check = 0; 
    int num = 0, sum = 0, mul = 1; 
  
    // Iterating through the digits 
    for (int i = 0; i <= len - 1; i++) { 
  
        // check whether s[i] is a character 
        // or a integer between 0 to 9 
        // and compute its equivalent BCD 
        if (s[i] >= 47 && s[i] <= 52) 
            cout << bitset<4>(s[i]) 
                 << " "; 
        else
            cout << bitset<4>(s[i] - 55) 
                 << " "; 
    } 
} 
  
// Driver Code 
int main() 
{ 
    string s = "11F"; 
  
    // Function Call 
    HexaDecimaltoBCD(s); 
  
    return 0; 
} 

Output:

0001 0001 1111

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My Personal Notes

C++

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