Given two positive integers m and n, the task is to write a program that checks whether m^n is greater than, less than or equal to n^m.
Input: m = 3, n = 10
Output: m^n > n^m
Explanation : 3^10=59049 which is greater than 10^3=1000
Input: m = 987654321, n = 123456987
Output: m^n < n^m
A naive approach is to compute m^n and n^m, which causes overflow when m and n are very large.
An efficient approach is to solve this problem using log.
Given LHS = m^n and RHS = n^m.
After taking log on both sides, LHS = n*log(m) and RHS = m*log(n)
Then compare the LHS and RHS.
m^n < n^m
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