PHP program to fetch data from localhost server database using XAMPP

XAMPP is a free and open source cross platform web server solution stack package developed by Apache which allow a web application to be easily tested on local web server. Here, we can manually create a relational database and store data in tabular form by going to this link. But to operate on localhost or for storing data first we have to start Apache and MySQL from XAMPP control panel.

Let for example, database name is server, table name is user_info having column name as ID, First Name, Username and Password and we have to fetch the data stored there. So, below is the PHP program whose task is to fetch data.

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

<?php 
// this php script is for connecting with database 
// data have to fetched from local server 
$mysql_host = 'localhost'; 
  
// user name is root 
$mysql_user = 'root'; 
  
// function to connect with database having  
// argument host and user name 
if (!@mysql_connect ($mysql_host, $mysql_user)) 
{ 
    die('Cannot connect to database'); 
} 
else
{ 
    // database name is server 
    if (@mysql_select_db('server')) 
    { 
        echo "Connection Success"; 
    } 
    else
    { 
        die('Cannot connect to database'); 
    } 
} 
?> 

Output:

Connection Success

Let above script is saved with name database.php inside htdocs folder of XAMPP installation.

<?php 
// going to use above code 
require 'database.php'; 
  
// printing column name above the data 
echo 'ID'.' '.'Name'.' '.'User'.' '.'Pass'.'<br>'; 
  
// sql query to fetch all the data 
$query = "SELECT * FROM `user_info`"; 
// mysql_query will execute the query to fetch data 
if ($is_query_run = mysql_query($query)) 
{ 
    // echo "Query Executed"; 
    // loop will iterate until all data is fetched 
    while ($query_executed = mysql_fetch_assoc ($is_query_run)) 
    { 
        // these four line is for four column 
        echo $query_executed['ID'].' '; 
        echo $query_executed['First Name'].' '; 
        echo $query_executed['Username'].' '; 
        echo $query_executed['Password'].'<br>'; 
    } 
} 
else
{ 
    echo "Error in execution"; 
} 
?> 

Output:

ID Name User Pass
1 Name1 user1 pass1
2 name2 user2 pass2
3 name3 pass3 pass3

For installing and working with XAMPP, refer to this link.

This article is contributed by Aditya Kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

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