PHP | Imagick displayImage() Function
Last Updated :
10 Jan, 2022
The Imagick::displayImage() function is an inbuilt function in PHP which is used to displays an image object.
Syntax:
bool Imagick::displayImage( $servername )
Parameters: This function accepts a single parameter $servername which is used to specify the server name.
Return Value: This function returns True on success.
Below programs illustrate the Imagick::displayImage() function in PHP:
Program:
<?php
$imagick = new Imagick(
$imagick ->displayImage(5);
header( "Content-Type: image/jpg" );
echo $imagick ->getImageBlob();
?>
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Output:
Program 2:
<?php
$string = "Computer Science portal for Geeks!" ;
$im = new Imagick();
$draw = new ImagickDraw();
$draw ->setFillColor( new ImagickPixel( 'green' ));
$draw ->setFontSize(50);
$matrix = $im ->queryFontMetrics( $draw , $string );
$draw ->annotation(0, 40, $string );
$im ->newImage( $matrix [ 'textWidth' ], $matrix [ 'textHeight' ],
new ImagickPixel( 'white' ));
$im ->drawImage( $draw );
$im ->setImageFormat( 'jpeg' );
header( "Content-Type: image/jpg" );
echo $im ->getImageBlob();
?>
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Output:
Reference: http://php.net/manual/en/imagick.displayimage.php
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