# Pentacontagon number

Given a number N, the task is to find Nth Pentacontagon number

A Pentacontagon number is class of figurate number. It has 50 – sided polygon called pentacontagon. The N-th pentacontagon number count’s the 50 number of dots and all others dots are surrounding with a common sharing corner and make a pattern. The first few pentacontagonol numbers are 1, 50, 147, 292 …

Examples:

Input: N = 2
Output: 50
Explanation:
The second pentacontagonol number is 50.
Input: N = 3
Output: 147

Approach: The N-th pentacontagon number is given by the formula:

• Nth term of s sided polygon = • Therefore Nth term of 50 sided polygon is •

Below is the implementation of the above approach:

## C++

 // C++ program for above approach #include  using namespace std;   // Finding the nth pentacontagon Number int pentacontagonNum(int n) {     return (48 * n * n - 46 * n) / 2; }   // Driver Code int main() {     int n = 3;     cout << "3rd pentacontagon Number is = "          << pentacontagonNum(n);       return 0; }   // This code is contributed by Akanksha_Rai

## C

 // C program for above approach #include  #include    // Finding the nth pentacontagon Number int pentacontagonNum(int n) {     return (48 * n * n - 46 * n) / 2; }   // Driver program to test above function int main() {     int n = 3;     printf("3rd pentacontagon Number is = %d",            pentacontagonNum(n));       return 0; }

## Java

 // Java program for above approach import java.util.*;   class GFG {   // Finding the nth pentacontagon number static int pentacontagonNum(int n) {     return (48 * n * n - 46 * n) / 2; }   // Driver code public static void main(String[] args) {     int n = 3;           System.out.println("3rd pentacontagon Number is = " +                                     pentacontagonNum(n)); } }   // This code is contributed by offbeat

## Python3

 # Python3 program for above approach    # Finding the nth pentacontagon Number  def pentacontagonNum(n):        return (48 * n * n - 46 * n) // 2   # Driver Code n = 3 print("3rd pentacontagon Number is = ",                     pentacontagonNum(n))    # This code is contributed by divyamohan123

## C#

 // C# program for above approach using System;   class GFG {   // Finding the nth pentacontagon number static int pentacontagonNum(int n) {     return (48 * n * n - 46 * n) / 2; }   // Driver code public static void Main(string[] args) {     int n = 3;           Console.Write("3rd pentacontagon Number is = " +                                pentacontagonNum(n)); } }   // This code is contributed by rutvik_56

## Javascript

 

Output:

3rd pentacontagon Number is = 147

Time Complexity: O(1)

Auxiliary Space: O(1)

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