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Output of Java Programs | Set 33 (Collections)

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Prerequisite: Java – Collections 1. What is the output of following Java Program?
import java.util.ArrayList;
class Demo {
public void show()
    {
        ArrayList<Integer> list = new ArrayList<Integer>();
        list.add(4);
        list.add(7);
        list.add(1);
        for (int number : list) {
            System.out.print(number + " ");
        }
    }
} public class Main {
public static void main(String[] args)
    {
        Demo demo = new Demo();
        demo.show();
    }
}

                    
A. Compilation Error B. 4 7 1 C. 1 4 7 D. None
Answer : B. 4 7 1
Explanation : List in java stores its elements in Sequential manner it maintains insertion order. List provides the ability of accessing elements using index.Collections are in the package util so we are importing java.util.ArrayList. 2. What is the output of following Java Program?
import java.util.LinkedList;
  
class Demo {
public void show()
    {
        LinkedList<String> list = new LinkedList<String>();
        list.add("Element1"); // line 6
        list.add("Element2");
        System.out.print(list.getFirst()); // line 8
    }
} public class Main {
public static void main(String[] args)
    {
        Demo demo = new Demo();
        demo.show();
    }
}

                    
A. Element1 B. Compilation Error at line 8 C. Runtime Error
Answer: A. Element1
Explanation : LinkedList has a getFirst() method . It returns an elements at Zero index. LinkedList also maintains its insertion order and provides easy accessing of elements. 3. What is the output of following Java Program?
import java.util.ArrayList;
class Demo {
public void show()
    {
        ArrayList<String> list = new ArrayList<String>();
        System.out.print(list.get(0));
    }
} public class Main {
public static void main(String[] args)
    {
        Demo demo = new Demo();
        demo.show();
    }
}

                    
A. ArrayIndexOutOfBoundException B. IndexOutOfBoundException C. null
Answer : B.IndexOutOfBoundException
Explanation : There is no element present in that index ‘0’ so it is IndexOutOfBoundException. In java, if we access the elements out of the index it provides ArrayIndexOutOfBoundException in array. In Collection. it provide IndexOutOfBoundException. 4. What is the Output of following Java Program?
import java.util.ArrayList;
  
class Demo {
public void show()
    {
        ArrayList<String> list = new ArrayList<String>();
        list.add("GeeksForGeeks_one"); // line 6
        list.add("GeeksForGeeks_two");
        System.out.print(list.getFirst()); // line 8
    }
} public class Main {
public static void main(String[] args)
    {
        Demo demo = new Demo();
        demo.show();
    }
}

                    
A. GeeksForGeeks_one B. Compilation Error C. Runtime Error
Answer: B. Compilation Error
Explanation: ArrayList doesn’t have method getFirst(). So it is compilation error.getmethod() is available only LinkedList. Therefore, it provide compilation error in this program. 5. What is the Output of following Java Program?
import java.util.LinkedList;
  
class Demo {
public void show()
    {
        LinkedList<String> list = new LinkedList<String>();
  
        System.out.print(list.getFirst());
    }
} public class Main {
public static void main(String[] args)
    {
        Demo demo = new Demo();
        demo.show();
    }
}

                    
A. null B. IndexOutOfBoundException C. NoSuchElementException
Answer: C. NoSuchElementException 
Explanation: There is no element in LinkedList so it return NoSuchElementException. NoSuchElementException is a RuntimeException thrown when there is no more element in it. NoSuchElementException extends RuntimeException.

Last Updated : 18 Sep, 2017
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